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01 Jun 2010, 05:14
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
82% (02:28) correct
18%
(02:47)
wrong
based on 1180
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One-sixth of the attendees at a certain convention are female students, two-thirds of the attendees are female, and one-third of the attendees are students. If 150 of the attendees are neither female nor students, what is the total number of attendees at the convention?
A. 300
B. 450
C. 600
D. 800
E. 900
A. 300
B. 450
C. 600
D. 800
E. 900
01 Jun 2010, 05:45
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sm0k3rz
Make a chart:
Attachment:
Chart.JPG [ 12.3 KiB | Viewed 29027 times ]
Next:
Female Non-student = (Total Female) - (Female Students) --> \(\frac{2}{3}x-\frac{1}{6}x=\frac{1}{2}x\);
Total Non-students = (Total) - (Total students) --> \(x-\frac{1}{3}x=\frac{2}{3}x\);
Total Non-students = (Female non-students) + (Male non-students) --> \(\frac{2}{3}x=\frac{1}{2}x+150\) --> \(x=900\).
Answer: E.
Hope it helps.
General Discussion
01 Jun 2010, 05:41
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Let no. of Attendee are A.
Now As per the condition of the problem stated above .
We have following population in the convention as Attendee.
Total no. of females = [2/3]*A
Total no. of females as student : [1/6]*A
Total no. of students = [1/3]*A
Total no. of male as student = [1/6]*A
Total no. of males = A - [2/3]*A = [1/3]A
No. of males which are not student = [1/3]A - [1/6]*A = 150
Hence A = 900
Total no of males who are not student will be the answer as it states it should be neither female nor student
So Answer is E
Now As per the condition of the problem stated above .
We have following population in the convention as Attendee.
Total no. of females = [2/3]*A
Total no. of females as student : [1/6]*A
Total no. of students = [1/3]*A
Total no. of male as student = [1/6]*A
Total no. of males = A - [2/3]*A = [1/3]A
No. of males which are not student = [1/3]A - [1/6]*A = 150
Hence A = 900
Total no of males who are not student will be the answer as it states it should be neither female nor student
So Answer is E
