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Updated on: 05 Mar 2016, 19:43
Originally posted by tonebeeze on 19 Oct 2010, 12:15.
Last edited by ENGRTOMBA2018 on 05 Mar 2016, 19:43, edited 1 time in total.
Last edited by ENGRTOMBA2018 on 05 Mar 2016, 19:43, edited 1 time in total.
Reformatted the question
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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If \(xy \neq 0\), what is the value of \(\frac{((x^2)^3 y^4)}{x}\)?
(1) \(x^3y^5 = \frac{6y}{x^2}\)
(2) \(x = 2y\)
(1) \(x^3y^5 = \frac{6y}{x^2}\)
(2) \(x = 2y\)
19 Oct 2010, 12:23
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tonebeeze
\(xy\neq{0}\) means that neither of unknowns equals to zero.
\(\frac{(x^2)^3*y^4}{x}=\frac{x^6*y^4}{x}=x^5*y^4=?\)
(1) \(x^3y^5=\frac{6y}{x^2}\) --> multiple by \(x^2\) --> \(x^5y^5=6y\) --> reduce by \(y\) --> \(x^5y^4=6\). Sufficient.
(2) \(x=2y\) --> \(x^5*y^4=(2y)^5*y^4=32y^9=?\) --> need to know the value of \(y\) (or \(x\)). Not sufficient.
Answer: A.
For more on exponents check Number Theory chapter of Math Book: math-number-theory-88376.html
Hope it helps.
19 Oct 2010, 14:29
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Thanks Bunuel. I apologize for the bad formatting. Won't happen again!
