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OA is B.

Why can't x be 04?

Sum of 0 + 4 = 4
04 is positive

Does GMAT not recognize this style?
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Hi aazhar,

The questions states that x is a two digit number, which can be in form of ab (\(a>0, b >=0\))
Also, a+b=4

using (1), x is odd => b is odd;
(a,b) = (1,3),(3,1), two possibilities. Insufficient.

using (b), \(2x < 44\) or \(x < 22\)
numbers will be 11,12,13,14,15,16,17,18,19,20,21
out of which only 13 has sum of digits as 4.
x is 13. Sufficient.

If we make 10th place digit as zero, the number reduces to single digit. (and thus, it can't be 04)

Regards,
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OA is B.

Why can't x be 04?

Sum of 0 + 4 = 4
04 is positive

Does GMAT not recognize this style?

We are told that x is a two-digit integer, whereas 04 is just 4 so its a single-digit integer. For a complete solution please refer to the posts above.
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Great! What I did was to assign values for x and its digits like this:

x=ab. We know from the stem that a+b=4.

[1] x is odd. NS, as there are 2 options.
There are 5 ways in which a+b=4, namely:
4+0, gives the 2 digit #40, even
3+1, gives the 2 digit #31, odd
2+2, gives the 2 digit #22, even
1+3, gives the 2 digit #13, odd
0+4, gives the #4, single digit and even

[2] 2x<44 --> x<22. NS, as there are multiple options.

[1,2] x<22 and odd. So, only 13 works.
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If the sum of the digits of the positive two-digit number x is 4, then x must be 13, 31, 22, or 40. We can rephrase this question as “Is the value of x 13, 31, 22 or 40?”

(1) INSUFFICIENT: If x is odd, x can be 13 or 31.

(2) SUFFICIENT: From the statement, 2*x < 44, so x < 22. This means that x must be 13.

The correct answer is B.
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Bunuel
enigma123
If the sum of the digits of the positive two-digit number x is 4, what is the value of x?

(1) x is odd.
(2) Twice the value of x is less than 44.

As OA is not given, I have got B. Please can I request to see my solution below and confirm whether its correct or not ?

Statement 1 --> x is ODD so x can be 13 and 31. Two values, therefore insufficient.


Statement 2 --> When x is 13 then twice the value will be 26 and when x is 31 it will be 62. But x cannot be 62 as the statement 2 says Twice the value of x is less than 44. Therefore x has to be 13. Hence B is my answer choice.

If the sum of the digits of the positive two-digit number x is 4, what is the value of x?

x can take the following 4 values: 13, 31, 22, or 40.

(1) x is odd --> x can still take two values: 13 or 31. Not sufficient.

(2) Twice the value of x is less than 44 --> only 13 satisfies this statement, so x=13. Sufficient.

Answer: B.

P.S. Your solution seems fine, except there are 4 values of x possible not just 2 (though this doesn't affect the answer in our case).



Hope it's clear.

well my solution worked out like this

x can be written as= 10 a+b---1
we are given a+b = 4 -----2
2-1= 9a=x-4
only 13 fits the solution so A is sufficient , therefore D
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Bunuel
enigma123
If the sum of the digits of the positive two-digit number x is 4, what is the value of x?

(1) x is odd.
(2) Twice the value of x is less than 44.

As OA is not given, I have got B. Please can I request to see my solution below and confirm whether its correct or not ?

Statement 1 --> x is ODD so x can be 13 and 31. Two values, therefore insufficient.


Statement 2 --> When x is 13 then twice the value will be 26 and when x is 31 it will be 62. But x cannot be 62 as the statement 2 says Twice the value of x is less than 44. Therefore x has to be 13. Hence B is my answer choice.

If the sum of the digits of the positive two-digit number x is 4, what is the value of x?

x can take the following 4 values: 13, 31, 22, or 40.

(1) x is odd --> x can still take two values: 13 or 31. Not sufficient.

(2) Twice the value of x is less than 44 --> only 13 satisfies this statement, so x=13. Sufficient.

Answer: B.

P.S. Your solution seems fine, except there are 4 values of x possible not just 2 (though this doesn't affect the answer in our case).



Hope it's clear.

well my solution worked out like this

x can be written as= 10 a+b---1
we are given a+b = 4 -----2
2-1= 9a=x-4
only 13 fits the solution so A is sufficient , therefore D

My friend,

If you want to find out the OA, you can check under the spoiler in the original post. It's B, not D. Plus, you are quoting the very post which gives TWO values of x possible 13 AND 31. Both of them fit even your solution.
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Consider x =10*a+b

a+b= 4 (given). What is the value of x?

Before we analyze options let us find the possible values of x
x can be 13,22,31,40 (Since the sum of digits is 4 and it is a double digit number)

1) x is odd...x maybe 13 or 31... Not sufficient. Strike off A, D
2) 2*x is less than 44.....x may be 13 only..(all other possible values give 2*x>=44) . Hence B alone is Sufficient.

Answer is B
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enigma123
If the sum of the digits of the positive two-digit number x is 4, what is the value of x?

(1) x is odd.
(2) Twice the value of x is less than 44.


Let the digits of x be a and b
Given a + b = 4
therefore a = b-4
X = 10a + b
Therefore X= 10(4-b)+b
X= 40-10b+b
X=40-9b
Also given: X is positive, and has 2 digits
To find: X

St1 : Does not help us much. hence not sufficient
St 2: 2X<44
Therefore X<22
40-9b<22
40-9(1) = 31
40-9(2) = 22
40-9(3)= 13
40-9(4) =4
Therefore we can see that the only assumption that meets all values is 40-9(3)
Hence
a+b=4
a+3=4
a=1
X=10a+b
X=13
Hence B is sufficient
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