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30 Jul 2012, 19:13
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
64% (01:55) correct
36%
(01:32)
wrong
based on 249
sessions
History
Date
Time
Result
Not Attempted Yet
31 Jul 2012, 01:13
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If x > y, is zx > yx?
Is \(zx > yx\)? --> is \(zx-yx>0\)? --> is \(x(z-y) >0\)?
(1) z > 0. Clearly insufficient.
(2) y < 0. Clearly insufficient.
(1)+(2) Now, remember that we can subtract inequalities with the signs in opposite direction --> subtract (2) from (1): \(z-y>0\). So, we know that the second multiply in \(x(z-y)\) is positive, but we still don't know the sign of \(x\): from the stem (\(x>y\)) and the second statement (\(y<0\)) the only thing we can deduce is that \(x\) is greater than negative number \(y\), hence \(x\) could be negative, positive or zero. Not sufficient.
Answer: E.
Hope it's clear.
Is \(zx > yx\)? --> is \(zx-yx>0\)? --> is \(x(z-y) >0\)?
(1) z > 0. Clearly insufficient.
(2) y < 0. Clearly insufficient.
(1)+(2) Now, remember that we can subtract inequalities with the signs in opposite direction --> subtract (2) from (1): \(z-y>0\). So, we know that the second multiply in \(x(z-y)\) is positive, but we still don't know the sign of \(x\): from the stem (\(x>y\)) and the second statement (\(y<0\)) the only thing we can deduce is that \(x\) is greater than negative number \(y\), hence \(x\) could be negative, positive or zero. Not sufficient.
Answer: E.
Hope it's clear.
General Discussion
