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Bunuel
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Triangles ABC and DEF are similar. What percent of the area of triangle DEF is triangle ABC?

(1) Sides AB and DE connect similar angles, and AB is 3 times DE

AB = 3 * DE

Area of T. ABC/Area of T. DEF = AB/DE

Area of T. ABC/Area of T. DEF = 1/3

Area of T. ABC = 33% of Area of T. DEF

Hence, =====> (1) is SUFFICIENT

(2) Side AB = 9

We only have information for 1 triangle and we do not know anything about the other triangle.

Hence, =====> (2), is IN SUFFICIENT

Hence, Answer is A
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Answer is A

(1) makes the two triangles similar and we know that for similar triangles, Area(ABC)/Area(PQR)=AB^2/PQ^2
So sufficient.

(2) doesn't give any information about PQR, or any thing to relate abc to pqr in any way. So insufficient.

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Referring to Bunuel resources

If two similar triangles have sides in the ratio\(\frac{x}{y}\), then their areas are in the ratio\(\frac{x^2}{y^2}\)


Statement 1 : AB is 3 times DE and since the both the triangles are similar area will be in ratio\(\frac{3^2}{1^2}\)

=> \(\frac{area ABC}{area DEF} = \frac{9}{1}\) = 900% Sufficient

Statement 2: No information related to side ration's of triangle, hence insufficient

Ans: A
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