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Test It

Statement 1 - Y = 15 ....yes
Y is equal to Sqrt15------No insufficient

Statement 2 Sqrt of Y is a multiple of 15, that means that the prime factors of Y contain the prime factors of 15
Sufficient
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1. y^2 is a multiple of 15

let y^2= 30= 15*2

y= \sqrt{15*2} which is definitely not a multiple of 15

let y^2= 225= 15*15

then y= \sqrt{225} = 15 (multiple of 15)

hence this statement is not sufficient

2. \sqrt{y} is a multiple of 15

let \sqrt{y}= 30

then y= 30^2= 15^2 * 2^2

this is definitely a multiple of 15

Hence second statement is sufficient.

Answer B
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282552
Is y a multiple of 15?

(1) y^2 is a multiple of 15
(2) The square root of y is a multiple of 15

since we are not explicitly told that y must be an integer, 1 is insufficient, because y might be sqrt(15), which is not a multiple of 15.

statement 2 alone says that sqrt(y)=multiple of 15. so y must be a multiple of 15 as well.
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282552
Is y a multiple of 15?

(1) y^2 is a multiple of 15
(2) The square root of y is a multiple of 15

Every now and then I miss one scenario and end up getting the question wrong.
Need to know if there are any set of specific checks that I can perform on these kind of questions so that I do not miss any scenario.

Please help.
I will provide OA after some discussion.

(1) y^2 is a multiple of 15
what is y= 15 ^1/2. In this case y is not a multiple of 15 but y^2 is.

(2) The square root of y is a multiple of 15.
let's say square root of y = 15 (minimum value)
so y = 225 (minimum value)

All values >15 with y^1/2 being multiple of 15, y will be multiple of 15

B is the answer
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Statement 1: INSUFFICIENT
Y square= 0, 15, 30
So, Y= 0, Square Root 15, Square Root 30.
Here 0 is a multiple of 15 but
Square Root 15 is NOT a multiple of 15.

Statement 2: Sufficient
SQRT (Y) = O, 15,30,.....15xp
So Y =0,15^2,(2x15)^2..(15xp)^2
So y is always a multiple of 15.

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