Bunuel
If x is a positive integer, is x^2 + 6x +10 odd?
(1) x^2 + 4x + 5 is odd
(2) x^2 + 3x + 4 is even
Kudos for a correct solution. MANHATTAN GMAT OFFICIAL SOLUTION:The question can first be simplified by noting that, if x is even, x^2 + 6x + 10 will be even, and if x is odd, x^2 + 6x+ 10 will be odd.
Thus, you can simplify this question: “Is x odd or even?” (A couple of shortcuts to save time in reaching that conclusion: the exponent on the first term can be ignored, since an even squared is still even and an odd squared is still odd. 6x will be even no matter what, since 6 is even, and obviously 10 is even no matter what. So, an even plus two evens is even, and an odd plus two evens is odd.)
(1) SUFFICIENT: You can plug in numbers or simply use number theory. If x is even, you get even + even + odd = odd, and if x is odd, you get odd + even + odd = even. Thus, since x^2 + 4x + 5 is odd, x is even.
(2) INSUFFICIENT: x^2 + 3x + 4 is actually even regardless of what integer is plugged in for x. If x is even, you get even + even + even = even, and if x is odd, you get odd + odd + even = even. Thus, x could be odd or even. Plugging in numbers will yield the same conclusion - x could be any integer.
Note that you should not factor any of the expressions above. If you wasted time factoring, remember: factoring is meaningless if you don’t have an equation set equal to zero! This problem was about number theory (or number testing), not factoring.
The correct answer is (A).