Last visit was: 26 Apr 2026, 16:39 It is currently 26 Apr 2026, 16:39
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,910
Own Kudos:
Given Kudos: 105,897
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,910
Kudos: 811,439
 [16]
2
Kudos
Add Kudos
14
Bookmarks
Bookmark this Post
User avatar
GMATinsight
User avatar
Major Poster
Joined: 08 Jul 2010
Last visit: 26 Apr 2026
Posts: 6,977
Own Kudos:
16,922
 [4]
Given Kudos: 128
Status:GMAT/GRE Tutor l Admission Consultant l On-Demand Course creator
Location: India
GMAT: QUANT+DI EXPERT
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
WE:Education (Education)
Products:
Expert
Expert reply
Schools: IIM (A) ISB '24
GMAT 1: 750 Q51 V41
Posts: 6,977
Kudos: 16,922
 [4]
2
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
manishkhare
Joined: 21 Jun 2014
Last visit: 15 May 2021
Posts: 69
Own Kudos:
418
 [2]
Given Kudos: 59
Location: United States
Concentration: General Management, Strategy
GMAT 1: 630 Q45 V31
GPA: 3.4
WE:Engineering (Computer Software)
GMAT 1: 630 Q45 V31
Posts: 69
Kudos: 418
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,910
Own Kudos:
811,439
 [2]
Given Kudos: 105,897
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,910
Kudos: 811,439
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

Question Type: Yes/No. The question asks: “Is x an even number?”

Given information in the question stem or diagram: x is a positive integer.

Statement 1: If x is divided by 3, the remainder is 2. This statement can be easily addressed by considering numbers and Playing Devil’s Advocate. First attempt to get an even number from Statement 1: The number 8 gives you a remainder of 2 when divided by 3. This is an even number so you have a “yes” answer. Next choose a number exactly 3 higher or lower than 8: 11 is an odd number and also gives a remainder of 2 when divided by 3. So 11 works but gives you a “no” answer. This statement is not sufficient, so eliminate choices A and D.

Statement 2: If x is divided by 5, the remainder is 2. This statement can be treated in the same way as Statement 1. First get a “yes” answer. If x = 12, then 12/5 = 2 remainder 2. Next choose a number exactly 5 above or below 12. If x = 7, then 7/5 = 1 remainder 2. So this works as well and gives you a “no” answer. This statement is also not sufficient, so eliminate choice B.

Together: Taken together you know that x must be 2 greater than a multiple of both 5 and 3. So x must yield a remainder of 2 when divided by 15. So 17 would work. 17/5 = 3 remainder 2, and 17/3 = 5 remainder 2. 17 is an odd number so you have a “no” answer. Now add 15 to 17 to get 32. 32 is an even number and will give you a “yes” answer. 32/5 = 6 remainder 2 and 32/3 = 10 remainder 2. So 32 satisfies both statements as well. Note: Number picking is of course not required to answer this question. With a good conceptual understanding of the number line, and quotient/remainder problems in particular, you can see quite clearly that the answer will be E in this problem. As is often the case, Arithmetic problems in Data Sufficiency can be quickly and reliably answered if you have a deep conceptual understanding of the subject matter.
User avatar
Temurkhon
Joined: 23 Jan 2013
Last visit: 06 Apr 2019
Posts: 408
Own Kudos:
325
 [2]
Given Kudos: 43
Schools: Cambridge'16
Schools: Cambridge'16
Posts: 408
Kudos: 325
 [2]
2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
x=3q+2
x=5r+2

3q=5r, q/r=5/3, so x can be even or odd

E
User avatar
stonecold
Joined: 12 Aug 2015
Last visit: 09 Apr 2024
Posts: 2,231
Own Kudos:
Given Kudos: 893
GRE 1: Q169 V154
GRE 1: Q169 V154
Posts: 2,231
Kudos: 3,644
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Given => x is a positive integer
WE need to examine it fro its even/odd property
Statement 1
here x=3k+2 for some k
x=2
x=5
From above two test cases we can say that this statement is insufficient
Statement 2
x=5m+2 for some m
x=2
x=7
from the above two test cases we can say that this statement is insufficient.
Combing the two statements
we can say that x=2+15p for some p
x=2
x=17
clearly from the above two test cases we can say that this statement is insufficient.
Hence E
User avatar
Abhishek009
User avatar
Board of Directors
Joined: 11 Jun 2011
Last visit: 17 Dec 2025
Posts: 5,902
Own Kudos:
Given Kudos: 463
Status:QA & VA Forum Moderator
Location: India
GPA: 3.5
WE:Business Development (Commercial Banking)
Posts: 5,902
Kudos: 5,456
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.


Kudos for a correct solution.

Plug in ad check

FROM STATEMENT - I ( INSUFFICIENT )

x = 5 , x/3 = remainder 2 ( x = Odd )
x = 8 , x/3 = remainder 2 ( x = Even )

Thus x can be even/Odd..

FROM STATEMENT - II ( INSUFFICIENT )

x = 7 , x/5 = remainder 2 ( x = Odd )
x = 12 , x/5 = remainder 2 ( x = Even )

Thus x can be even/Odd..

FROM STATEMENT - I & II ( INSUFFICIENT )

Since, we do not have a unique value of x we can not state whether x = Even/Odd

Hence, Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed, answer will be (E)..
User avatar
Alexey1989x
Joined: 05 Dec 2016
Last visit: 20 May 2023
Posts: 187
Own Kudos:
Given Kudos: 49
Concentration: Strategy, Finance
GMAT 1: 620 Q46 V29
GMAT 1: 620 Q46 V29
Posts: 187
Kudos: 98
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

Question Type: Yes/No. The question asks: “Is x an even number?”

Given information in the question stem or diagram: x is a positive integer.

Statement 1: If x is divided by 3, the remainder is 2. This statement can be easily addressed by considering numbers and Playing Devil’s Advocate. First attempt to get an even number from Statement 1: The number 8 gives you a remainder of 2 when divided by 3. This is an even number so you have a “yes” answer. Next choose a number exactly 3 higher or lower than 8: 11 is an odd number and also gives a remainder of 2 when divided by 3. So 11 works but gives you a “no” answer. This statement is not sufficient, so eliminate choices A and D.

Statement 2: If x is divided by 5, the remainder is 2. This statement can be treated in the same way as Statement 1. First get a “yes” answer. If x = 12, then 12/5 = 2 remainder 2. Next choose a number exactly 5 above or below 12. If x = 7, then 7/5 = 1 remainder 2. So this works as well and gives you a “no” answer. This statement is also not sufficient, so eliminate choice B.

Together: Taken together you know that x must be 2 greater than a multiple of both 5 and 3. So x must yield a remainder of 2 when divided by 15. So 17 would work. 17/5 = 3 remainder 2, and 17/3 = 5 remainder 2. 17 is an odd number so you have a “no” answer. Now add 15 to 17 to get 32. 32 is an even number and will give you a “yes” answer. 32/5 = 6 remainder 2 and 32/3 = 10 remainder 2. So 32 satisfies both statements as well. Note: Number picking is of course not required to answer this question. With a good conceptual understanding of the number line, and quotient/remainder problems in particular, you can see quite clearly that the answer will be E in this problem. As is often the case, Arithmetic problems in Data Sufficiency can be quickly and reliably answered if you have a deep conceptual understanding of the subject matter.

Hi Bunuel, thanks for careful explanation on the problem.
It took me around 6~ minutes to get options satisfying both (1) & (2) and yield in "E". Your formula for finding LCM of quotients and adding the remainder is really useful and can save plenty of time in real exam conditions. I'm studying for GMAT using MGM 6th edition course however it doesn't provide for this approach. Would you please give a link to a source or explain more how to tackle similar problems in case we have different remainders (2 & 3 for instance) or if one quotient is a multiple of another one.

Thanks in advance!
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 26 Apr 2026
Posts: 109,910
Own Kudos:
811,439
 [1]
Given Kudos: 105,897
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,910
Kudos: 811,439
 [1]
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Alexey1989x
Bunuel
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.


Kudos for a correct solution.

VERITAS PREP OFFICIAL SOLUTION:

Question Type: Yes/No. The question asks: “Is x an even number?”

Given information in the question stem or diagram: x is a positive integer.

Statement 1: If x is divided by 3, the remainder is 2. This statement can be easily addressed by considering numbers and Playing Devil’s Advocate. First attempt to get an even number from Statement 1: The number 8 gives you a remainder of 2 when divided by 3. This is an even number so you have a “yes” answer. Next choose a number exactly 3 higher or lower than 8: 11 is an odd number and also gives a remainder of 2 when divided by 3. So 11 works but gives you a “no” answer. This statement is not sufficient, so eliminate choices A and D.

Statement 2: If x is divided by 5, the remainder is 2. This statement can be treated in the same way as Statement 1. First get a “yes” answer. If x = 12, then 12/5 = 2 remainder 2. Next choose a number exactly 5 above or below 12. If x = 7, then 7/5 = 1 remainder 2. So this works as well and gives you a “no” answer. This statement is also not sufficient, so eliminate choice B.

Together: Taken together you know that x must be 2 greater than a multiple of both 5 and 3. So x must yield a remainder of 2 when divided by 15. So 17 would work. 17/5 = 3 remainder 2, and 17/3 = 5 remainder 2. 17 is an odd number so you have a “no” answer. Now add 15 to 17 to get 32. 32 is an even number and will give you a “yes” answer. 32/5 = 6 remainder 2 and 32/3 = 10 remainder 2. So 32 satisfies both statements as well. Note: Number picking is of course not required to answer this question. With a good conceptual understanding of the number line, and quotient/remainder problems in particular, you can see quite clearly that the answer will be E in this problem. As is often the case, Arithmetic problems in Data Sufficiency can be quickly and reliably answered if you have a deep conceptual understanding of the subject matter.

Hi Bunuel, thanks for careful explanation on the problem.
It took me around 6~ minutes to get options satisfying both (1) & (2) and yield in "E". Your formula for finding LCM of quotients and adding the remainder is really useful and can save plenty of time in real exam conditions. I'm studying for GMAT using MGM 6th edition course however it doesn't provide for this approach. Would you please give a link to a source or explain more how to tackle similar problems in case we have different remainders (2 & 3 for instance) or if one quotient is a multiple of another one.

Thanks in advance!

Check the links below for more:

Divisibility and Remainders on the GMAT

Divisibility Tips

Theory on remainders problems
Tips on remainders

Units digits, exponents, remainders problems

DS remainders problems
PS remainders problems

DS divisibility problems
PS divisibility problems
User avatar
HKD1710
User avatar
Retired Moderator
Joined: 22 Jun 2014
Last visit: 26 Feb 2021
Posts: 960
Own Kudos:
Given Kudos: 182
Location: India
Concentration: General Management, Technology
GMAT 1: 540 Q45 V20
GPA: 2.49
WE:Information Technology (Computer Software)
GMAT 1: 540 Q45 V20
Posts: 960
Kudos: 4,663
Kudos
Add Kudos
Bookmarks
Bookmark this Post
stmt-1: If x is divided by 3, the remainder is 2
x = 5 (odd) / 3 , remainder is 2
x = 2 (Even) / 3 , remainder is 2

stmt-1: If x is divided by 5, the remainder is 2
x = 7 (odd) / 5 , remainder is 2
x = 2 (Even) / 5 , remainder is 2

Stmt-1 + stmt-2: remainder is 2 when divided by 15
x = 17(odd) / 15 , remainder is 2
x = 2 (Even) / 15 , remainder is 2

Answer E :)
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 26 Apr 2026
Posts: 22,286
Own Kudos:
26,538
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,538
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.

We need to determine whether x is an even number.

Statement One Alone:

If x is divided by 3, the remainder is 2.

Statement one alone is not sufficient to answer the question. For example, x could be 5, which is an odd number, or x could be 8, which is an even number.

Statement Two Alone:

If x is divided by 5, the remainder is 2.

Statement two alone is not sufficient to answer the question. For example, x could be 7, which is an odd number, or x could be 12, which is an even number.

Statements One and Two Together:

Using the statements together, we see that the first number that fulfills both statements is n = 2, which is an even number.

To determine the next value in the list, we can use the least common multiple of 3 and 5, which is 3 x 5 = 15. Thus, the next number that could be x is 2 + (5 x 3) = 17, which is an odd number. Thus, the two statements together are still not sufficient to answer the question.

Answer: E
User avatar
Archit3110
User avatar
Major Poster
Joined: 18 Aug 2017
Last visit: 26 Apr 2026
Posts: 8,631
Own Kudos:
Given Kudos: 243
Status:You learn more from failure than from success.
Location: India
Concentration: Sustainability, Marketing
GMAT Focus 1: 545 Q79 V79 DI73
GMAT Focus 2: 645 Q83 V82 DI81
GPA: 4
WE:Marketing (Energy)
Products:
GMAT Focus 2: 645 Q83 V82 DI81
Posts: 8,631
Kudos: 5,191
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Is the positive integer x an even number?

(1) If x is divided by 3, the remainder is 2.
(2) If x is divided by 5, the remainder is 2.


Kudos for a correct solution.

#1If x is divided by 3, the remainder is 2.
x can be 2 ,5 ; insufficient
#2
If x is divided by 5, the remainder is 2
x can 2,7 insufficient
from 1 &2
x can be 2,17,32 where x is divided by 15
insufficient
OPTION E
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,991
Own Kudos:
Posts: 38,991
Kudos: 1,118
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109910 posts
498 posts
212 posts