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18 Apr 2017, 04:52
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
65% (01:46) correct
35%
(02:07)
wrong
based on 500
sessions
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A clothing boutique bought a particular shirt for c dollars and sold the shirt for p dollars. If either c or p is equal to $100, then the boutique’s profit on the sale was what percentage of its cost?
(1) p/c = 6/5
(2) p − c = 20
(1) p/c = 6/5
(2) p − c = 20
18 Apr 2017, 08:35
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Cost Price of the shirt = $ c
Selling Price of the shirt = $ p
Profit = $ p - c
boutique’s profit on the sale was what percentage of its cost = (p-c) *100 /c %
If either c or p is equal to $100,
(1) p/c = 6/5
p = 6c/5
(p-c) *100 /c % => [6c/5 - c]*100/c => [c/5]*100/c = 20%
Hence this statement is sufficient.
(2) p − c = 20
If P is 100, then C is 80
(p-c) *100 /c % => 20 *100/80 = 25%
If C is 100, then P is 120
(p-c) *100 /c % => 20 *100/100 = 20%
As we are getting two different percentage, this statement is not sufficient.
Answer is A
Selling Price of the shirt = $ p
Profit = $ p - c
boutique’s profit on the sale was what percentage of its cost = (p-c) *100 /c %
If either c or p is equal to $100,
(1) p/c = 6/5
p = 6c/5
(p-c) *100 /c % => [6c/5 - c]*100/c => [c/5]*100/c = 20%
Hence this statement is sufficient.
(2) p − c = 20
If P is 100, then C is 80
(p-c) *100 /c % => 20 *100/80 = 25%
If C is 100, then P is 120
(p-c) *100 /c % => 20 *100/100 = 20%
As we are getting two different percentage, this statement is not sufficient.
Answer is A
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Concentration: Finance, Entrepreneurship
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18 Apr 2017, 08:48
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This is the DS question and we need to test whether the statement is sufficient to answer.
1) p/c=6/5.
Let's test if p=100 then p/c=600/500=1.2 => 20% profit, the same if c=100.
Sufficient.
2) If p=100, then c=100-20=80.
If c=100, then p=100+20=120.
100/80≠120/100.
Two possibilities mean insufficient.
Answer A.
1) p/c=6/5.
Let's test if p=100 then p/c=600/500=1.2 => 20% profit, the same if c=100.
Sufficient.
2) If p=100, then c=100-20=80.
If c=100, then p=100+20=120.
100/80≠120/100.
Two possibilities mean insufficient.
Answer A.
