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Bunuel
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(1) x + y = 3y – x
Rewriting this equation, we get x=y.
Whatever the value of x and y, x-y is always 0.Hence sufficient.

(2) x + y = x^3 + y^3
This is possible when both x and y are 1 and -1.
Adding both these values will not yield an unique answer.
Hence insufficient. (Option A)

please correct if i am wrong

-1-(-1) =0

and
1-1 =0

hence unique answers




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This is what i meant. if x=1,y=-1, we get x-y = 2
But if x and y are 1, their difference is 0.

Corrected the solution! Hope that helps
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Statement 1 will give x = y. regardless of the value of x and y, answer will be zero. Sufficient.

Statement 2 x + y = x^3 + y^3. (x + y) = (x+y)(x^2 + y^2 - xy) or x^2 + y^2 = 1 + xy. This option doesn't lead anywhere. Insufficient.

Option A should be correct.
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