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rocker007
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Statement 1 - solving the two equations x=-1/4 & y=8 hence xy=-2
Statement 2 - since it the same line hence the values of x & y will be the same as from statement 1. Hence answer is D

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dheerajkaushik90
If y + 40x + 2 = 0, what is the value of xy?

(1) 16x = –4y + 28

(2) 13y = 91 – 52x
\(y + 40x + 2 = 0\) --------- (i)

(1) \(16x = –4y + 28\)

\(4x = -y + 7\)

\(y + 4x = 7\) -------- (ii)

Subtracting (i) and (ii) we can find the value of \(x\) and \(y\). Hence we can find the value of \(xy\).

Hence I is Sufficient.

(2) \(13y = 91 – 52x\)

\(y = 7 - 4x\)

\(y + 4x = 7\) ---------- (iii)

Subtracting (i) and (iii) we can find the value of \(x\) and \(y\). Hence we can find the value of \(xy\).

Hence II is Sufficient.

Answer (D)...
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What is the OA for the question

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dheerajkaushik90
If y + 40x + 2 = 0, what is the value of xy?

(1) 16x = –4y + 28

(2) 13y = 91 – 52x

Target question: What is the value of xy?

Given: y + 40x + 2 = 0
Rearrange to get: 40x + y = -2

IMPORTANT: We are given one linear equation. If we given a different linear equation, then we can be certain to solve the system of equations for x and y, which means we can determine the value of xy
So, we need only determine whether each statement provides a linear equation that is different from the given linear equation (40x + y = -2)

Statement 1: 16x = –4y + 28
Divide both sides by 4 to get: 4x = -y + 7
Add y to both sides: 4x + y = 7
This second linear equation is different from the given linear equation (40x + y = -2)
This means we COULD solve the system of equations for x and y, which means we COULD determine the value of xy
Since we COULD answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 13y = 91 – 52x
Divide both sides by 13 to get: y = 7 - 4x
Add 4x to both sides: 4x + y = 7
This is the same equation that we have in statement 1.
So, if statement 1 is sufficient, we can also be certain that statement 2 is SUFFICIENT

Answer: D

Cheers,
Brent
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