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07 Oct 2017, 08:50
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Difficulty:
55%
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Question Stats:
55% (01:11) correct
45%
(01:33)
wrong
based on 249
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What is the value of y ?
1) \(\frac{4xy+2y}{6x+3} = y-3\)
2) \(x=2\)
1) \(\frac{4xy+2y}{6x+3} = y-3\)
2) \(x=2\)
07 Oct 2017, 09:50
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What is the value of y ?
(1) \(\frac{4xy+2y}{6x+3} = y-3\);
Factor our 2y from the numerator and 3 from the denominator: \(\frac{2y(2x+1)}{3(2x+1)} = y-3\);
Reduce by 2x+1: \(\frac{2y}{3} = y-3\);
Cross-multiply: \(2y = 3y - 9\);
Solve to get y =9.
Sufficient.
(2) \(x=2\). Nothing about y. Not sufficient.
Answer: A.
(1) \(\frac{4xy+2y}{6x+3} = y-3\);
Factor our 2y from the numerator and 3 from the denominator: \(\frac{2y(2x+1)}{3(2x+1)} = y-3\);
Reduce by 2x+1: \(\frac{2y}{3} = y-3\);
Cross-multiply: \(2y = 3y - 9\);
Solve to get y =9.
Sufficient.
(2) \(x=2\). Nothing about y. Not sufficient.
Answer: A.
07 Oct 2017, 10:00
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@bunuel,
For reducing by 2x+1, shouldnt we be sure that x is not equal to -1/2.
Sent from my iPhone using GMAT Club Forum
For reducing by 2x+1, shouldnt we be sure that x is not equal to -1/2.
Sent from my iPhone using GMAT Club Forum
