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asthagupta
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Updated on: 17 Jun 2018, 03:23
Originally posted by asthagupta on 17 Jun 2018, 02:59.
Last edited by asthagupta on 17 Jun 2018, 03:23, edited 1 time in total.
Last edited by asthagupta on 17 Jun 2018, 03:23, edited 1 time in total.
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
20% (02:03) correct
80%
(01:23)
wrong
based on 5
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Date
Time
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Not Attempted Yet
If all variable are integers, is x+y–z+tx+y–z+t even?
(1) x+y+tx+y+t is even
(2) t∗zt∗z is odd
I am not sure what is the exact answer as i have a different answer and the source where i read this have a different answer. Will update official answer after discussion on the forum.
(1) x+y+tx+y+t is even
(2) t∗zt∗z is odd
I am not sure what is the exact answer as i have a different answer and the source where i read this have a different answer. Will update official answer after discussion on the forum.
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
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17 Jun 2018, 03:14
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asthagupta
\(x+y-z+ tx+y-z+t=x+tx+t+2y-2z\)..
2y-2z will be even, so Is x+tx+t even?
If only one is odd and other even..
Odd+even*odd+even=odd
Both odd..
O+O*O+O=O
Both even..
E+E*E+E=E
So we are looking if both x and t are even...
1)x+y+tx+y+t is even..
x+tx+t+2y is even, so x+tx+t is even..
Ans YES
Sufficient
2)t*z*t*z is odd..
This means ans is NO
So sufficient
D
However both statements are giving different answers
This Question is Locked Due to Poor Quality
Hi there,
The question you've reached has been archived due to not meeting our community quality standards. No more replies are possible here.
Looking for better-quality questions? Check out the 'Similar Questions' block below
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