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08 Jul 2018, 23:45
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
73% (01:04) correct
27%
(01:09)
wrong
based on 229
sessions
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If Danielle ran a race at a constant speed, at what time did she finish?
(1) Danielle started the race at 8:00 a.m.
(2) At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
(1) Danielle started the race at 8:00 a.m.
(2) At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
09 Jul 2018, 00:15
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If Danielle ran a race at a constant speed, at what time did she finish?
(1) Danielle started the race at 8:00 a.m.
Nothing about speed..
insuff
(2) At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
now we have a time frame 10:00 am - 09:30 am AND also the fraction of race completed = \((\frac{2}{3}-\frac{1}{2})\) of total
So (2/3-1/2)=1/6 in half an hour and full in 6*1/2=3hrs
Since half the race at 0930, another 3/2 hrs to complete it.. thus 0930+0130=1100
so suff
B
(1) Danielle started the race at 8:00 a.m.
Nothing about speed..
insuff
(2) At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
now we have a time frame 10:00 am - 09:30 am AND also the fraction of race completed = \((\frac{2}{3}-\frac{1}{2})\) of total
So (2/3-1/2)=1/6 in half an hour and full in 6*1/2=3hrs
Since half the race at 0930, another 3/2 hrs to complete it.. thus 0930+0130=1100
so suff
B
09 Jul 2018, 00:28
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Let us look at:
Statement 1: At what time Danielle started wouldn't totally help in answering at what time would she finish. So, straight-way, this option ain't sufficient. Eliminate A and D. Although this information might be useful further, let's see...
Statement 2: At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
Let us assume the total distance of the race to be D.
Statement implies that in 30 mins (9:30 a.m.-10:00 a.m.) Danielle covered the distance = (2/3)D-D/2=D/6.
I.E.
1) D/6 distance in 30 mins
2) Danielle had covered D/2 by 9:30 AM, and hence had to cover the next D/2. Using 1) above, D/2 would be covered in 90 mins. Therefore 9:30 AM plus another 90 mins = 11 AM.
So, Danielle will complete the race by 11 AM.
HENCE Statement 2 suffices. Therefore, answer is B. Hope this was useful.
Happy preparing. Good Luck!
Statement 1: At what time Danielle started wouldn't totally help in answering at what time would she finish. So, straight-way, this option ain't sufficient. Eliminate A and D. Although this information might be useful further, let's see...
Statement 2: At 9:30 a.m. Danielle was halfway through the race, and at 10:00 a.m., she was 2/3 of the way through the race.
Let us assume the total distance of the race to be D.
Statement implies that in 30 mins (9:30 a.m.-10:00 a.m.) Danielle covered the distance = (2/3)D-D/2=D/6.
I.E.
1) D/6 distance in 30 mins
2) Danielle had covered D/2 by 9:30 AM, and hence had to cover the next D/2. Using 1) above, D/2 would be covered in 90 mins. Therefore 9:30 AM plus another 90 mins = 11 AM.
So, Danielle will complete the race by 11 AM.
HENCE Statement 2 suffices. Therefore, answer is B. Hope this was useful.
Happy preparing. Good Luck!
