Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
27% (02:27) correct
73%
(02:35)
wrong
based on 316
sessions
History
Date
Time
Result
Not Attempted Yet
If x and y are non zero numbers less than 1, is \((y^4 - x^4) > (y^3 - x^5)\) ?
(1) y > 0
(2) y > |x|
(1) y > 0
(2) y > |x|
04 Aug 2018, 08:51
Kudos
Bookmarks
Rearrange the terms
y^4 -y^3 > -x^5 + x^4
factor, so the question now is:
is y^3(y - 1) > - (x^4) (x - 1)?
1) y>0
so y is between 0 and 1
This means the LHS is negative (because (y-1) is negative, and y^3 is positive)
RHS is always positive (because (x-1) is always negative since x is less than 1, -(x^4) is always negative, so their product is always positive)
If LHS is always negative and RHS is always positive, this means that RHS>LHS, so statement 1 is sufficient to determine that the inequality is false.
2) y> |x|
This means y is positive i.e. y>0
The statement is therefore equivalent to statement 1, and we can use the same logic to determine that the inequality is false
Hence, the answer is D
y^4 -y^3 > -x^5 + x^4
factor, so the question now is:
is y^3(y - 1) > - (x^4) (x - 1)?
1) y>0
so y is between 0 and 1
This means the LHS is negative (because (y-1) is negative, and y^3 is positive)
RHS is always positive (because (x-1) is always negative since x is less than 1, -(x^4) is always negative, so their product is always positive)
If LHS is always negative and RHS is always positive, this means that RHS>LHS, so statement 1 is sufficient to determine that the inequality is false.
2) y> |x|
This means y is positive i.e. y>0
The statement is therefore equivalent to statement 1, and we can use the same logic to determine that the inequality is false
Hence, the answer is D
04 Aug 2018, 10:21
Kudos
Bookmarks
ankit7055
OA:D
Is \((y^4 - x^4) > (y^3 - x^5)\)?
Is \(y^3(y-1)>x^4(1-x)\)?
Statement 1 : \(y > 0\)
\(0<y<1\)
L.H.S \(y^3(y-1)\) would always be negative
For \(x\), there can be 2 cases,
1) \(0<x<1\)
2) \(x<0\)
R.H.S will be always positive, as \(x^4\) is +ve, \((1-x)\) would give +ve value in both of the cases
So There is definite answer to Is \((y^4 - x^4) > (y^3 - x^5)\)? , That is No
Statement 1 alone is sufficient
Statement 2 : \(y > |x|\)
it means \(y\) is positive, i,e \(y>0\) same as statement 1
So There is definite answer to Is \((y^4 - x^4) > (y^3 - x^5)\)? , That is No
Statement 2 alone is sufficient
700 level IMO. 
