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05 Sep 2018, 23:38
Kudos
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
63% (01:45) correct
37%
(01:54)
wrong
based on 109
sessions
History
Date
Time
Result
Not Attempted Yet
What is the total area of the figure, if the area of the shaded region is 100 and MK = 10?
(1) x = y = 45
(2) QL = 10
Attachment:
image008.jpg [ 4.4 KiB | Viewed 3051 times ]
Bunuel
Question stem:- What is the area of the quadrilateral KMNL?
St1:- x = y = 45
Refer the enclosed diagram, \(\triangle{NQL}\), \(\triangle{KPO}\), and \(\triangle{KMP}\) are isosceles right angled triangles(45-45-90) form. sides are in the ratio \(x:x:\sqrt{2}x\)
So base=height=10 and hypotenuse=\(10\sqrt{2}\)
Hence area of \(\triangle{NQL}\)=Area of \(\triangle{KPO}\)=Area of \(\triangle{KMP}\) (Base and height are known, area can be determined)
Total area of figure=Area of shaded region(100)+3*Area of triangle NQL
Sufficient.
St-2:- QL = 10
Area of the figure will be different at different measures of x.
Insufficient.
Moderator Note: Fixed typo. Ans. (A)
Attachments
Area.JPG [ 17.05 KiB | Viewed 2727 times ]
06 Sep 2018, 08:45
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Hi,
I think lot of assumption are made while solving this problem.
1. Shaded region is square.
2. KL is parallel to MN
Question stem says nothing about above assumptions.
Can I make such assumptions while solving DS problems.
I think lot of assumption are made while solving this problem.
1. Shaded region is square.
2. KL is parallel to MN
Question stem says nothing about above assumptions.
Can I make such assumptions while solving DS problems.
