Bunuel wrote:

What is the total area of the figure, if the area of the shaded region is 100 and MK = 10?

(1) x = y = 45

(2) QL = 10

Attachment:

The attachment **image008.jpg** is no longer available

Question stem:- What is the area of the quadrilateral KMNL?

St1:-

x = y = 45Refer the enclosed diagram, \(\triangle{NQL}\), \(\triangle{KPO}\), and \(\triangle{KMP}\) are isosceles right angled triangles(45-45-90) form. sides are in the ratio \(x:x:\sqrt{2}x\)

So base=height=10 and hypotenuse=\(10\sqrt{2}\)

Hence area of \(\triangle{NQL}\)=Area of \(\triangle{KPO}\)=Area of \(\triangle{KMP}\) (Base and height are known, area can be determined)

Total area of figure=Area of shaded region(100)+3*Area of triangle NQL

Sufficient.

St-2:- QL = 10

Area of the figure will be different at different measures of x.

Insufficient.

~~Ans. (D)~~**Edit: **Fixed typo. Ans. (A)

Attachments

Area.JPG [ 17.05 KiB | Viewed 640 times ]

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Regards,

PKN

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