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09 Sep 2018, 08:03
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
43% (01:53) correct
57%
(02:03)
wrong
based on 63
sessions
History
Date
Time
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Not Attempted Yet
What is the value of b?
(1) The radius of the circle is 6.
(2) ac = 12
Attachment:
image009.jpg [ 4.47 KiB | Viewed 2149 times ]
10 Sep 2018, 12:47
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PQ=a^2+b^2
QR=b^2+c^2
Because PQR is a right angled triangle, we have PQ^2+QR^2=PR^2.
(a^2+b^2)+(b^2+c^2)=(a+c)^2
(a^2+2*b^2+c^2)=a^2+c^2+2ac
2b^2=2ac
b^2=ac
b=sq.root of ac=sq.root of 12.
Hi Bunuel, shouldn't the answer be B?
QR=b^2+c^2
Because PQR is a right angled triangle, we have PQ^2+QR^2=PR^2.
(a^2+b^2)+(b^2+c^2)=(a+c)^2
(a^2+2*b^2+c^2)=a^2+c^2+2ac
2b^2=2ac
b^2=ac
b=sq.root of ac=sq.root of 12.
Hi Bunuel, shouldn't the answer be B?
23 Sep 2018, 15:33
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Hi rajudantuluri,
It is not mentioned anywhere that PR is the diameter of the circle, so you can not assume that PQR is a right angled triangle.
The answer is E.
It is not mentioned anywhere that PR is the diameter of the circle, so you can not assume that PQR is a right angled triangle.
The answer is E.
