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17 Sep 2018, 22:07
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
57% (01:08) correct
43%
(01:13)
wrong
based on 76
sessions
History
Date
Time
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Not Attempted Yet
Does the graph of y = mx^2 + h intersect the x–axis?
(1) m < 0
(2) h > 0
(1) m < 0
(2) h > 0
18 Sep 2018, 02:10
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Bunuel
For a quadratic equation \(ax^2+bx+c\) to intersect with x axis \(b^2-4ac≥0\)
i.e. for \(y = mx^2 + h, 0-4mh ≥0\)
Combining both statements answers the questions as we need signs of both m and h hence
Answer:Option C
15 Jan 2020, 04:32
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If graph of y = mx^2 + h intersects the x–axis, mx^2 + h=0 must have real roots
Discriminant of mx^2 + h=0 is greater than or equal to 0
b^2-4ac ≥ 0
0-4mh ≥0
mh≤0
Basically our question stem is whether m and h have same signs
Statement 1- We have no idea about h (Insufficient)
Statement 2- We have no idea about m (Insufficient)
Combining both statements
m and h have opposite signs
Sufficient
Discriminant of mx^2 + h=0 is greater than or equal to 0
b^2-4ac ≥ 0
0-4mh ≥0
mh≤0
Basically our question stem is whether m and h have same signs
Statement 1- We have no idea about h (Insufficient)
Statement 2- We have no idea about m (Insufficient)
Combining both statements
m and h have opposite signs
Sufficient
Bunuel
