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In the figure above, what is the length of AC ?
(1) x + y = 13
(2) xy = 36
Attachment:
length.jpg [ 13.34 KiB | Viewed 8440 times ]
31 Oct 2018, 10:13
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1. AC= 2(x+y) =2*13 = 26 Suff
2. If xy=36, x,y have diff possible pair if they are strictly integers e.g., (1,36),(2,18) etc ..... if we consider non-integers there will be more e.g., \((\frac{36}{7} , 7)\), \((\frac{36}{11},11)\).... etc..... so x+y will be having varied results for each pair. --Not Suff .......................Thus Ans A
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22 Jul 2019, 18:53
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AC = 2x +2y
(AC/2) = x+y
Statement 1
x+y=13 -->sufficient
statement 2
xy = 36
would lead to a quadratic. IS
(AC/2) = x+y
Statement 1
x+y=13 -->sufficient
statement 2
xy = 36
would lead to a quadratic. IS
