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Bunuel
Does x have at least 3 prime factors?

(1) x = 5b, where b is a positive integer.
(2) b = 2c, where c is a positive integer.

#1
x=5b
x=5; no
x=50;no
x=60 ; yes 3 prime factors 2^2*3*5
in sufficient
#2
b=2c
no info of x in sufficeint
from1 &2
@ b= 2-10 ; no 3 prime factors i.e x=50
but @b>12 ; >=3 prime factors i.e x=60 onwards
in sufficient
IMO E
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I agree with this even though the answer says E. I feel like even if c=2, then we still have 2,5, and 1 as prime factors
leomanna10
IMO C

1) clearly insufficient. For example

if b= 1. ----> x has 2 prime factors 1 and 5;
if b= 3 -----> x has 3 prime factor 1, 3 and 5;

2) claearly insufficient

1 + 2) x= 5*2C = 10c. If we multiply 10 for any positive integer, we always have at list 3 prime factors: 1,2,5

for example

if c= 1 -----> X = 10*1 = 10 in this case x has 3 prime factors 1,2,5
if c=19 -----> X = 190 in this case has at least 3 positive factors 1,2,5

Is my answer right? O someone can give an explanation?
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lily123400
I agree with this even though the answer says E. I feel like even if c=2, then we still have 2,5, and 1 as prime factors


Does x have at least 3 prime factors?


(1) x = 5b, where b is a positive integer.
(2) b = 2c, where c is a positive integer.

No, the correct answer is E, not C. When combining the statements we get x = 2 * 5 * c.

If c = 1, x = 2 * 5, which has only two primes 2 and 5 (1 is NOT a prime number).
If c = 7, x = 2 * 5 * 7, which has three primes 2, 5 and 7.
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