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This is DS question and so we need to jump to options as there are nothing much on question stem.
Option -1 : 75 -x when divided by 3 gives reminder 1.
when we divide the whole expression (75 -x) , 75 is divisible by 3 , remainder 0. and again when x is divided remainder is 1.
So this gives us that X when divided by 3 gives 1 as remainder.

Option-2 : X^2 divided by 3 , remainder 1.
Not necessarily when x divided by 3 will give same remainder. For example of 5^2 = 25 , when divided by 3 gives 1 as remaindre, but 5 gives 2 as remainder.
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Statement 1
75-x=3p+1
(3*25)-x=3p+1
Rearranging
X=3(25-p)-1
Therefore, remainder is 2
Sufficient

Statement 2
(X^2) /3 having remainder 1
Implies that x/3 has remainder either 1 or 2
Hence, insufficient

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Statement 1
Given that (75-x)= 1 mod 3
(0-r) mod 3= 1 mod 3
0-r=1
r=-1
or r=(3-1)=2
sufficient

Statement 2
x^2= 1 mod 3
x=±1 mod 3
r can be 1 or 2
insufficient

akhilvarma8
What is the remainder when positive integer x is divided by 3?

(1) When 75 – x is divided by 3, the remainder is 1.

(2) When x^2 is divided by 3, the remainder is 1.

Looking for a good solution as I am unable to get how the answer is different from mine.
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STATEMENT 1:
"When 75 – x is divided by 3, the remainder is 1."
A Shortcut to such question:
In finding out REMAINDERS,
(a) if SOMETHING in the NUMERATOR is completely divisible by THE DENOMINATOR, WORK with the remaining figures in the NUMERATOR.
(b) SUBTRACTION OR ADDITION is the same thing there.


Back to the statement 1: "When 75 – x is divided by 3, the remainder is 1."
In finding out REMAINDERS,
(a) As 75 in the NUMERATOR is completely divisible by 3 (THE DENOMINATOR), Question becomes: (When – x is divided by 3, the remainder is 1)
(b) SUBTRACTION OR ADDITION is the same thing there: So, -x and x are SAME thing for REMAINDER PURPOSE.
Question becomes: (When x is divided by 3, the remainder is 1).
SUFFICIENT.
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BelalHossain046
STATEMENT 1:
"When 75 – x is divided by 3, the remainder is 1."
A Shortcut to such question:
In finding out REMAINDERS,
(a) if SOMETHING in the NUMERATOR is completely divisible by THE DENOMINATOR, WORK with the remaining figures in the NUMERATOR.
(b) SUBTRACTION OR ADDITION is the same thing there.


Back to the statement 1: "When 75 – x is divided by 3, the remainder is 1."
In finding out REMAINDERS,
(a) As 75 in the NUMERATOR is completely divisible by 3 (THE DENOMINATOR), Question becomes: (When – x is divided by 3, the remainder is 1)
(b) SUBTRACTION OR ADDITION is the same thing there: So, -x and x are SAME thing for REMAINDER PURPOSE.
Question becomes: (When x is divided by 3, the remainder is 1).
SUFFICIENT.

STATEMENT 2: When x^2 is divided by 3, the remainder is 1
For remainders from such such square values, I Create 3 line chart.

(1) Possible value of x^2=1,4 [Adding 3 with previous one to find next one]
(2) So, x=1,2,..........[Square Root of the value of x^2]
(3) REMAINDER when x is divided by 3=1, 2.
INSUFFICIENT
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