Events & Promotions
|
|
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Apr 2512:30 AM EDT
-01:30 AM EDT
At one point, she believed GMAT wasn’t for her. After scoring 595, self-doubt crept in and she questioned her potential. But instead of quitting, she made the right strategic changes. The result? A remarkable comeback to 695. Check out how Saakshi did it.
Apr 2610:00 AM EDT
-11:00 AM EDT
The Target Test Prep course represents a quantum leap forward in GMAT preparation, a radical reinterpretation of the way that students should study. Try before you buy with a 5-day, full-access trial of the course for FREE!
Apr 2711:00 AM EDT
-12:00 PM EDT
Prefer video-based learning? The Target Test Prep OnDemand course is a one-of-a-kind video masterclass featuring 400 hours of lecture-style teaching by Scott Woodbury-Stewart, founder of Target Test Prep and one of the most accomplished GMAT instructors
Apr 2808:00 AM PDT
-11:00 AM PDT
Whether you are just beginning your MBA journey or fine-tuning your path to a 700+ score, GMAT Day is designed to give you a competitive edge.
16 Aug 2019, 01:47
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
66% (00:44) correct
34%
(00:48)
wrong
based on 168
sessions
History
Date
Time
Result
Not Attempted Yet
A box contains only pens, pencils, and pads. If an item is randomly selected from the box, what is the probability that the item will be either a pencil or a pad?
(1) The probability that the item will be pad is 1/4.
(2) The probability that the item will be pen is 1/3.
(1) The probability that the item will be pad is 1/4.
(2) The probability that the item will be pen is 1/3.
vijyband99
Joined: 25 Mar 2017
Last visit: 23 Oct 2025
Posts: 21
Own Kudos:
Given Kudos: 111
Location: India
Schools: IIMA PGPX"20 ISB '20 IIMC PGPEX"20 Kellogg '21 Marshall '21 Ross '21 Sloan '21 Smeal'21 IIMB
GMAT 1: 650 Q49 V31
GMAT 2: 700 Q47 V39
GPA: 3.1
Products:
Schools: IIMA PGPX"20 ISB '20 IIMC PGPEX"20 Kellogg '21 Marshall '21 Ross '21 Sloan '21 Smeal'21 IIMB
GMAT 2: 700 Q47 V39
Posts: 21
Kudos:
8
18 Aug 2019, 05:01
Kudos
Bookmarks
Let P(Pencil) be probability of finding a pencil. Similarly we will use P(Pen) and P(Pad) in our solution.
What we need to find is P ( either Pencil or Pad).
P(either Pencil or Pad) = P( not finding a Pen)
Statement 1
P(Pad)=1/4
It does not help us find P(Pencil)
Not sufficient
Statement 2
P(Pen)=1/3
We have P (not finding a Pen) = 1 - P(Pen)= 1 - 1/3 = 2/3
SUfficient
Answer: B
What we need to find is P ( either Pencil or Pad).
P(either Pencil or Pad) = P( not finding a Pen)
Statement 1
P(Pad)=1/4
It does not help us find P(Pencil)
Not sufficient
Statement 2
P(Pen)=1/3
We have P (not finding a Pen) = 1 - P(Pen)= 1 - 1/3 = 2/3
SUfficient
Answer: B
20 Aug 2019, 04:06
Kudos
Bookmarks
The event of selecting a pencil is mutually exclusive to the event of selecting a pad. Therefore, the probability of selecting a pencil or a pad will be the cumulative of the two probabilities.
From statement I, we know the probability of selecting a pad, but not for the pencil. Statement I is insufficient.
Answer options A and D can be eliminated. Possible answer options are B, C or E.
From statement II we know that the probability of selecting a pen is \(\frac{1}{3}\). Therefore, the cumulative probability of selecting a pencil or a pad = 1 – \(\frac{1}{3}\) = \(\frac{2}{3}\).
Statement II is sufficient. Answer options C and E can be eliminated.
The correct answer option is B.
Hope this helps!
From statement I, we know the probability of selecting a pad, but not for the pencil. Statement I is insufficient.
Answer options A and D can be eliminated. Possible answer options are B, C or E.
From statement II we know that the probability of selecting a pen is \(\frac{1}{3}\). Therefore, the cumulative probability of selecting a pencil or a pad = 1 – \(\frac{1}{3}\) = \(\frac{2}{3}\).
Statement II is sufficient. Answer options C and E can be eliminated.
The correct answer option is B.
Hope this helps!
