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09 Aug 2020, 21:32
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
42% (02:05) correct
58%
(02:28)
wrong
based on 67
sessions
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In ∆OAB the point O is the origin, B is on X-axis, point A is in 1st quadrant and OA < AB. Is area of ∆OAB > 60?
1) Coordinates of Point A are (5, 12)
2) Coordinates of Point B are (12, 0)
1) Coordinates of Point A are (5, 12)
2) Coordinates of Point B are (12, 0)
Source: https://www.GMATinsight.com
Archit3110
09 Aug 2020, 22:12
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for given ∆ OAB ; O is 0,0 and given condition that OA<AB ; target is area of ∆ OAB >60
#1Coordinates of Point A are (5, 12) ;
so point B would be √(5-x)^2+(12)^2 >13 or say x(x-10)>0 ; x>10 ; such that base OB least is 10.1 and the area of ∆ is least 1/2*10.1*12 ; 60.1 hence sufficient
#2 Coordinates of Point B are (12, 0)
here with given condition OA<AB ; we can have both yes & no cases of area eg A (5,2) and B (12,0) and A 5,12 and B (12,0) insufficient ;
OPTION A correct
#1Coordinates of Point A are (5, 12) ;
so point B would be √(5-x)^2+(12)^2 >13 or say x(x-10)>0 ; x>10 ; such that base OB least is 10.1 and the area of ∆ is least 1/2*10.1*12 ; 60.1 hence sufficient
#2 Coordinates of Point B are (12, 0)
here with given condition OA<AB ; we can have both yes & no cases of area eg A (5,2) and B (12,0) and A 5,12 and B (12,0) insufficient ;
OPTION A correct
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