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04 Aug 2021, 01:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
78% (00:57) correct
22%
(00:56)
wrong
based on 147
sessions
History
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Time
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What percent of the boys and girls in a certain class own a bicycle?
(1) One-third of the boys in the class own a bicycle.
(2) Two-thirds of the girls in the class own a bicycle.
(1) One-third of the boys in the class own a bicycle.
(2) Two-thirds of the girls in the class own a bicycle.
04 Aug 2021, 05:46
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Q: What is the proportion of boys and girls in class owning a bicycle?
1) 1/3 of boys own bicycle (not sufficient)
2) 2/3 of girls own bicycle (not sufficient)
1) + 2) still not sufficient because the question depends on the proportion of boys and girls. If B:G changes, then the answer changes. (not sufficient)
Ans: E
1) 1/3 of boys own bicycle (not sufficient)
2) 2/3 of girls own bicycle (not sufficient)
1) + 2) still not sufficient because the question depends on the proportion of boys and girls. If B:G changes, then the answer changes. (not sufficient)
Ans: E
04 Aug 2021, 06:10
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Solution:
Let the number of boys be \(= B\) and number of boys who own a bicycle \(= B'\).
Similarly, let the number of girls be \(= G\) and number of girls who own a bicycle \(= G'\).
So, we need the value of \(\frac{(B'+G')}{(B+G)}\times 100\)
Statement 1: One-third of the boys in the class own a bicycle.
This statement tells us \(B'=\frac{1}{3} \times B\). But their is no information on girls.
Hence statement 1 alone is not sufficient. Thus we can eliminate options A and D.
Statement 2: Two-third of the girls in the class own a bicycle.
This statement tells us \(G'=\frac{2}{3} \times G\). But their is no information on Boys.
Hence statement 2 alone is also not sufficient. Thus we can eliminate option B also.
Combining the 2 statements:
Statement 1 gives us \(B'=\frac{B}{3}\) and \(G'=\frac{2G}{3}\)
We need the value of \(\frac{(B'+G')}{(B+G)}\times 100\)
So, \(B'+G'=\frac{B}{3}+\frac{2G}{3}=\frac{(B+2G)}{3}\)
Thus, \(\frac{(B'+G')}{(B+G)}\times 100=\frac{(B+2G)}{(2(B+G))}\times 100=\frac{(B+2G)}{(2B+2G)}\times 100\)
Even after combining it is not sufficient to get the answer. We need relation (ratio, percentage or fraction) between \(B\) and \(G\) to get our answer.
Hence the right answer is Option E.
Let the number of boys be \(= B\) and number of boys who own a bicycle \(= B'\).
Similarly, let the number of girls be \(= G\) and number of girls who own a bicycle \(= G'\).
So, we need the value of \(\frac{(B'+G')}{(B+G)}\times 100\)
Statement 1: One-third of the boys in the class own a bicycle.
This statement tells us \(B'=\frac{1}{3} \times B\). But their is no information on girls.
Hence statement 1 alone is not sufficient. Thus we can eliminate options A and D.
Statement 2: Two-third of the girls in the class own a bicycle.
This statement tells us \(G'=\frac{2}{3} \times G\). But their is no information on Boys.
Hence statement 2 alone is also not sufficient. Thus we can eliminate option B also.
Combining the 2 statements:
Statement 1 gives us \(B'=\frac{B}{3}\) and \(G'=\frac{2G}{3}\)
We need the value of \(\frac{(B'+G')}{(B+G)}\times 100\)
So, \(B'+G'=\frac{B}{3}+\frac{2G}{3}=\frac{(B+2G)}{3}\)
Thus, \(\frac{(B'+G')}{(B+G)}\times 100=\frac{(B+2G)}{(2(B+G))}\times 100=\frac{(B+2G)}{(2B+2G)}\times 100\)
Even after combining it is not sufficient to get the answer. We need relation (ratio, percentage or fraction) between \(B\) and \(G\) to get our answer.
Hence the right answer is Option E.
