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08 Oct 2021, 01:30
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
57% (02:09) correct
43%
(02:00)
wrong
based on 191
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Mark has fewer than 9 coins. Each coin is either a quarter (worth $0.25) or a dime (worth $0.10). How many dimes does Mark have?
(1) The total value of Mark’s coins is $1.70
(2) Mark has three times as many quarters as he has dimes.
(1) The total value of Mark’s coins is $1.70
(2) Mark has three times as many quarters as he has dimes.
08 Oct 2021, 02:48
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1) \(0.25y + 0.1x = 1.70\)
where \(y + x < 9\)
Then \(y = 6\) and \(x = 2\)
SUFFICIENT
2) \(0.25y + 0.1x \)
where \(y + x < 9\)
\(y:x = 3:1\)
Which means
\(y = 3 ; x = 1\)
or
\(y = 6 ; x = 2\)
INSUFFICIENT
Answer A
where \(y + x < 9\)
Then \(y = 6\) and \(x = 2\)
SUFFICIENT
2) \(0.25y + 0.1x \)
where \(y + x < 9\)
\(y:x = 3:1\)
Which means
\(y = 3 ; x = 1\)
or
\(y = 6 ; x = 2\)
INSUFFICIENT
Answer A
08 Oct 2021, 07:18
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Correct Option A
Given:
1. Mark has fewer than 9 coins = (x + y < 9)
2. Quarter (worth $0.25) or a dime (worth $0.10) ($0.25q + $0.1d)
Find: How many dimes does Mark have?
(1) The total value of Mark’s coins is $1.70
$0.25q + $0.1d = $1.7
With pug in number in equation
$0.25*(6) + $0.1(2) = $1.7 ---Conditon 1 satisfy
q + d < 9 = 6 + 2 = (8 < 9) max value of sum of q & d but less than 9 ----Condition 2 satisy
SUFFICIENT
(2) Mark has three times as many quarters as he has dimes
quaters = 3 dimes
q = 3 ; d = 1 (3 + 1 = 4) ------Less than 9
q = 6; d = 2 (6 + 2 = 8) ------ Less than 9
with two option - statement 2 is Not Sufficient
Given:
1. Mark has fewer than 9 coins = (x + y < 9)
2. Quarter (worth $0.25) or a dime (worth $0.10) ($0.25q + $0.1d)
Find: How many dimes does Mark have?
(1) The total value of Mark’s coins is $1.70
$0.25q + $0.1d = $1.7
With pug in number in equation
$0.25*(6) + $0.1(2) = $1.7 ---Conditon 1 satisfy
q + d < 9 = 6 + 2 = (8 < 9) max value of sum of q & d but less than 9 ----Condition 2 satisy
SUFFICIENT
(2) Mark has three times as many quarters as he has dimes
quaters = 3 dimes
q = 3 ; d = 1 (3 + 1 = 4) ------Less than 9
q = 6; d = 2 (6 + 2 = 8) ------ Less than 9
with two option - statement 2 is Not Sufficient
