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Bunuel
The original price of a computer was increased by x% to reach its current price. If Elena used a coupon that allowed her to purchase the computer at a y% discount off the current price, was the price at which she purchased the computer less than the original price of the computer?

(1) x = 12 and y < 12
(2) y > 9

Net percentage change is given by \(x - y -\frac{xy}{100}\)

Question: \(x - y -\frac{xy}{100}\) < 0

\(100(x - y) -xy < 0\)

Statement 1

(1) x = 12 and y < 12

x - y is positive.

100(x - y) < xy

As we do not know the exact value of x and y, we cannot conclude on the inequality. Hence, the statement alone is not sufficient. We can eliminate A and D.

Statement 2

(2) y > 9

Not sufficient, as we do not know the value of x. Eliminate B.

Combined

x = 12 and 9 < y < 12

Case 1: y \(\approx\) 12

\(100(x - y) \approx 0\)

\(100(x - y) - xy < 0\)

In this case, the net percentage change is negative.

Case 2: y \(\approx\) 9

\(100(12 - 9) \approx 300\)

\(300 - 108 > 0\)

In this case, the net percentage change is positive.

As we have two contradicting results, the statements combined are not sufficient.

Option E
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Bunuel
The original price of a computer was increased by x% to reach its current price. If Elena used a coupon that allowed her to purchase the computer at a y% discount off the current price, was the price at which she purchased the computer less than the original price of the computer?

(1) x = 12 and y < 12
(2) y > 9

When you increase A by say 10%, and then reduce by same %, 10%, the reduction includes not only 10% on x but also 10% on the increased amount, which is 10% of A.

Thus, increasing by x% and reducing by x% would surely give a smaller amount.
=> \(y\geq x\) will give you a decreased amount.

But if y<x, then the answer would depend on relation between x and y.

(1) x = 12 and y < 12
If the amount is 100, then the increase is 12.
Then y% of the increased amount will be equal to 12 when \(112*\frac{y}{100}=12\)
\(y=\frac{1200}{112}=\frac{112*10+80}{112}=10+\frac{80}{112} \)
So \(y>10+\frac{80}{112}\) will give lower value than initial amount.
Here, y could be 10 or 11 giving different answers.
Insufficient

(2) y > 9
Nothing about x.
Insufficient

Combined.
y can still be 10 or 11, giving different answers.
Insufficient

E
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Bunuel
The original price of a computer was increased by x% to reach its current price. If Elena used a coupon that allowed her to purchase the computer at a y% discount off the current price, was the price at which she purchased the computer less than the original price of the computer?

(1) x = 12 and y < 12
(2) y > 9

Let the original price = 100.

Statements combined:
Current price = 100 + 12% of 100 = 112

Case 1: y = just a bit less than 12
12% of 112 = (10% of 112 + 2% of 112) = 11.2 + 2.24 = 13.44
Implication:
Since the discount must actually be LESS than 12%, the discount in dollars must be LESS than 13.44.
If the discount = 13, we get:
Purchase price = 112 - 13 = 99
Since the purchase price is less than the original price, the answer to the question stem is YES.

Case 2: y = just a bit more than 9
9% of 112 = (0.09)(112) = 10.08
Implication:
Since the discount must actually be more MORE 9%, the discount in dollcars must be MORE than 10.08.
If the discount = 11, we get:
Purchase price = 112 - 11 = 101
Since the purchase price is NOT less than the original price, the answer to the question stem is NO.

Since the answer is YES in Case 1 but NO in Case 2, the two statements combined are INSUFFICIENT.

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Pick a number for the price of the computer. I chose $100.

1) x = 12%

Therefore new price is $112.

At y = 11%, you would say [(100-11)/100] * 112 = 99. So yes it's less.
Choose anything less than 12 for y. I chose 0.
At y=0%, the price is 112 so no.

You have a yes/no so insufficient.

2)

We don't know what x is. The computer's price could've been increased by 1% or 1000000000000% percent. Since we know y > 9 then there are cases where it DOES and DOESN'T work.

You have a yes/no so insufficient.

E
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Bunuel
The original price of a computer was increased by x% to reach its current price. If Elena used a coupon that allowed her to purchase the computer at a y% discount off the current price, was the price at which she purchased the computer less than the original price of the computer?

(1) x = 12 and y < 12
(2) y > 9
Essentially, this is a mark-up discount question and requires only 1 calculation. Consider the original price to be the cost price. The price is marked up by x% and then a discount of y% is given. The question is whether there was a loss or not.

(1) x = 12 and y < 12

This I know is not sufficient. Mark up of 12% is on cost price and discount is given on the greater marked up price. So a lower discount will wipe out the entire mark up. But we don't know how much lower y actually is.
Not sufficient.

(2) y > 9

No value for x so certainly not sufficient.

Both together, let me find the value of y for which there will be no profit no loss i.e. she purchased the computer at original price.

\((1 + \frac{12}{100}) * DiscountMultiplier ­= 1\)

\(Discount Multiplier = \frac{100}{112} \)

If y were 9, discount multiplier would be \(\frac{91}{100}\)

Now the question is, which is greater: \(\frac{100}{112} or \frac{91}{100}\)

When I increase 100 (the denominator of second fraction) by 12%, I get 112, the denominator of first fraction. When I increase 91 (the numerator of 2nd fraction by 9 which is 10% of 91, I already get the numerator of first fraction.
It means first fraction is smaller than second fraction. Hence I need a greater discount than y = 9 so that the selling price = cost price. Since y > 9, it is possible that selling price is more than cost price, equal to cost price or less than cost price.

Hence this not sufficient and answer is (E)

If the last part is a bit too un-intuitive, think of it this way:

Discount percentage is \(\frac{12}{112} * 100 = 10.something = y\)

So if y = 9.5% say, then her purchase price is higher than original price but if y = 11%, then her purchase price is lower than original price. ­Since both values of y are acceptable as per the 2 statements, we cannot say whether her purchase price was lower than original price.

Answer (E)


Method 2:

Alternatively think of this as successive percentage changes. You increase something by x% and then reduce it by y%. When will the overall impact be nothing?
If x = 12%
\(\frac{112}{100} * \frac{100}{112}\) will give us 1 i.e. no change.

100/112 is a decrease of 12/112 which is 10.something percent.
So if y = 9.5% say, then her purchase price is higher than original price but if y = 11%, then her purchase price is lower than original price. ­Since both values of y are acceptable as per the 2 statements, we cannot say whether her purchase price was lower than original price.


Note that both methods are actually the same. They are just different ways of thinking about it. After all, mark up is an application of successive percentage changes.
The concept of multiplier is discussed in this video.
Successive percentage changes are discussed here.
­
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chetan2u

When you increase A by say 10%, and then reduce by same %, 10%, the reduction includes not only 10% on x but also 10% on the increased amount, which is 10% of A.

Thus, increasing by x% and reducing by x% would surely give a smaller amount.
=> \(y\geq x\) will give you a decreased amount.

But if y<x, then the answer would depend on relation between x and y.
 
­This is a key principle that will help you avoid this kind of trap on other questions. Many people will wrongly assume that a 10% increase and 10% decrease will cancel each other out. As we become more mindful and proactively avoid these potential traps, we gain a huge advantage over the competition!
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Bunuel
The original price of a computer was increased by x% to reach its current price. If Elena used a coupon that allowed her to purchase the computer at a y% discount off the current price, was the price at which she purchased the computer less than the original price of the computer?

(1) x = 12 and y < 12
(2) y > 9
­Let the original price be p. Final price after price increase and discount becomes x*(100+x/100)*(100-y/100).

From statement 1, x is fixed but we will get different values of the final price for y<12. Insufficient.
In statement 2, x is unknown. Insufficient.

Combining 1 and 2, if we consider y=10, the final price becomes 1.008p -> greater than p.
If we consider y=11, the final price becomes 0.9968p -> less than p. Insufficient. Option (E) is correct.
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­Stm1 :
-> Let the original price = 100
-> Since x= 12, current price becomes 112
Finding the boundary value of y at which purchase price = original price
-> 112 * (1-y/100) = 100
-> 1 - y/100 = 100/112
-> y/100 = 12/112
-> y = 1200/112 = 10.xy

y must be greater than 10.xy for purchase price to be less than original price
Given y< 12
1) If y=11 -> answer is Y
2) If y=10 -> answer is N

Not sufficient

Stmt 2 : y>9
-> Since x is not given, markup can be anything. Clearly not sufficient

Stmt 1 + 2
-> 9<y<12 -> again y can be 11 (answer : Y) or 10 (answer : N).
-> Not sufficient

Answer : E­
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let original price be p.

Current price = p((100 + x)/100)
Elena’s price = ((100 - y)/100) · p((100 + x)/100)

We want: ((100 - y)/100) · ((100 + x)/100) · p < p or (100 - y)(100 + x) < 10,000

x = 12, y < 12

(100 - y)(112) < 10,000 = 11200 - 112y < 10,000
If y = 1: 11088 < 10000 → No
If y = 11: 9968 < 10000 → Yes
Not sufficient.

y > 9
Alone: not sufficient.

1) and 2) together

x = 12, and 9 < y < 12

If y = 11 → Yes
If y = 10 → No

Still not sufficient.

Answer: E
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