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11 Dec 2025, 23:39
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
73% (00:50) correct
27%
(00:37)
wrong
based on 70
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What is the total cost of six pencils and four notebooks?
(1) Ten pencils and nine notebooks cost $11.50.
(2) Twelve pencils and eight notebooks cost $11.00.
(1) Ten pencils and nine notebooks cost $11.50.
(2) Twelve pencils and eight notebooks cost $11.00.
msignatius
12 Dec 2025, 00:57
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Haha, this one almost deceived me; great question, an alert mind needed!
We need the total cost of 6 pencils, or 6p (p = pencil), and 4 notebooks, or 4n (n = notebook).
Statement I: It won't really be enough, isn't it? This says 10p + 9n = $11.50. The way to find 6p + 4n from this, will be to find the price of one pen or one notebook in the statement I equation, but we get multiple solutions. 10 * $0.61 (if the price of a pencil is assumed to be 61 cents) will give us $6.1, from which we can calculate that each notebook is $0.6, or a total of $5.4 (which adds with the $6.1 to give us $11.50). Now if the price of each pencil was $0.7, we would get $7 for the pencils + $4.5 for the notebooks, at $0.5 per notebook. This too gives us the required $11.50.
In other words, for the 6p + 4n equation, this gives us two contradicting answers. 6*0.61 + 4*0.6 = $6.06; and 6*0.7 + 4*0.5 = $6.2.
Statement II: This is where the trick comes in. I could have applied the same logic here as statement I, combine this with Statement II, get the right answer, and incorrectly mark C, but then I noticed that 12p + 8n = $11.00, has an LHS that is exactly double of the equation the question needs you to solve (6p + 4n). So, we simply divide the 12p + 8n = $11.00, the whole thing by 2, to get 6p + 4n = $5.50.
Statement II should be enough with that, correct answer B.
We need the total cost of 6 pencils, or 6p (p = pencil), and 4 notebooks, or 4n (n = notebook).
Statement I: It won't really be enough, isn't it? This says 10p + 9n = $11.50. The way to find 6p + 4n from this, will be to find the price of one pen or one notebook in the statement I equation, but we get multiple solutions. 10 * $0.61 (if the price of a pencil is assumed to be 61 cents) will give us $6.1, from which we can calculate that each notebook is $0.6, or a total of $5.4 (which adds with the $6.1 to give us $11.50). Now if the price of each pencil was $0.7, we would get $7 for the pencils + $4.5 for the notebooks, at $0.5 per notebook. This too gives us the required $11.50.
In other words, for the 6p + 4n equation, this gives us two contradicting answers. 6*0.61 + 4*0.6 = $6.06; and 6*0.7 + 4*0.5 = $6.2.
Statement II: This is where the trick comes in. I could have applied the same logic here as statement I, combine this with Statement II, get the right answer, and incorrectly mark C, but then I noticed that 12p + 8n = $11.00, has an LHS that is exactly double of the equation the question needs you to solve (6p + 4n). So, we simply divide the 12p + 8n = $11.00, the whole thing by 2, to get 6p + 4n = $5.50.
Statement II should be enough with that, correct answer B.
12 Dec 2025, 01:08
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Hello,
What is the total cost of six pencils and four notebooks?
(1) Ten pencils and nine notebooks cost $11.50.
As per this we cannot answer
Hence Insufficient
(2) Twelve pencils and eight notebooks cost $11.00.
12 pencil and 8 note books cost $11
so if we divide by 2
then we can get the answer for
6 pencil and 4 notebook
Hence this statement is sufficient
Answer B is correct
What is the total cost of six pencils and four notebooks?
(1) Ten pencils and nine notebooks cost $11.50.
As per this we cannot answer
Hence Insufficient
(2) Twelve pencils and eight notebooks cost $11.00.
12 pencil and 8 note books cost $11
so if we divide by 2
then we can get the answer for
6 pencil and 4 notebook
Hence this statement is sufficient
Answer B is correct
