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25 Dec 2025, 02:48
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
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Question Stats:
53% (01:56) correct
47%
(01:58)
wrong
based on 162
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In Country X and Country Y, lunch for the vast majority of high schoolers is the free lunch provided at their school cafeteria. In Country X, the average high-school cafeteria lunch (AHCL) contains about twice the amount of sugar compared with the AHCL in Country Y. In which of the two countries does the average high schooler consume more sugar per day?
(1) For the average high schooler in Country Y, the average amount of sugar across all the meals of the day is similar to that contained in the AHCL in Country X.
(2) In Country X, the average high schooler has one fewer meal per day compared with Country Y.
(1) For the average high schooler in Country Y, the average amount of sugar across all the meals of the day is similar to that contained in the AHCL in Country X.
(2) In Country X, the average high schooler has one fewer meal per day compared with Country Y.
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28 Dec 2025, 12:09
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Shouldnt ans be option C ? My logic is as follows:
Bunuel, kingbucky can you please look into this question and provide with the correct reasoning ?
Let AHCL in country Y = a.
So AHCL in country X = 2a.
Option (i) :- Let total no. of meals in country Y = n.
So Avg. sugar across all meals = ( Total sugar across all meals / n ) = 2a.
But we dont know the number of meals in country X. Hence insufficent.
Option (ii) :- We dont know about the sugar content of meals except for lunch. Hence insufficient.
Option (i) + (ii) :
No. of meals in country Y = n.
No. of meals in country X = n - 1.
Avg. sugar across all meals for country Y = ( Total sugar across all meals / n ) = 2a / n. (As per option (i))
In the worst case we assume that all the meals except for lunch in country X had 0 sugar. Then sugar consumed by avg high schooler in country X = (AHCL + sugar content of other meals ) / (n - 1)
= (2a + 0) / (n - 1). = 2a / ( n - 1 )
For country Y we have average sugar content = 2a / n
Hence in the worst case country X will have more sugar content then country Y. So answer should be C as per the above reasoning.
Bunuel, kingbucky can you please look into this question and provide with the correct reasoning ?
Let AHCL in country Y = a.
So AHCL in country X = 2a.
Option (i) :- Let total no. of meals in country Y = n.
So Avg. sugar across all meals = ( Total sugar across all meals / n ) = 2a.
But we dont know the number of meals in country X. Hence insufficent.
Option (ii) :- We dont know about the sugar content of meals except for lunch. Hence insufficient.
Option (i) + (ii) :
No. of meals in country Y = n.
No. of meals in country X = n - 1.
Avg. sugar across all meals for country Y = ( Total sugar across all meals / n ) = 2a / n. (As per option (i))
In the worst case we assume that all the meals except for lunch in country X had 0 sugar. Then sugar consumed by avg high schooler in country X = (AHCL + sugar content of other meals ) / (n - 1)
= (2a + 0) / (n - 1). = 2a / ( n - 1 )
For country Y we have average sugar content = 2a / n
Hence in the worst case country X will have more sugar content then country Y. So answer should be C as per the above reasoning.
29 Dec 2025, 11:59
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This question got me but yes answer is E. Let me explain with few numbers
COuntry X: Breakfast, Lunch in canteen(sugar ratio mentioned as twice of Y), dinner
Country Y Breakfast, Lunch in canteen(sugar ratio with X mentioned), dinner
Asked who eats more sugar. That will not just depend on lunch but other meals as well. Could be possible 'Y's breakfast and dinner is10 times sugar content of Breakfast and dinner. Also almost lunch is had by everyone - but on avg how much is tendency to skip breakfast or lunch - with this background lets make a formula Sugar content = Sugar in Breakfast*avg probability to have Breakfast
+ Sugar in Lunch*avg probability to have Lunch + Sugar in Dinner*avg probability to have Dinner.
Now
(1) For the average high schooler in Country Y, the average amount of sugar across all the meals of the day is similar to that contained in the AHCL in Country X.
We know avg sugar across the meal for 1 day not the probability to have. X could eat more likely in 1 day and Y could eat less. Weighted avgs - its not about what sugar content is present but consumed which is why probability to eat is imp
No
(2) In Country X, the average high schooler has one fewer meal per day compared with Country Y.
Well this answer's the second part I addressed in statement 1. Reject alone
Now together - I have avg of day and avg of probability but is this correct. Lets check mathematically
Sugar content B=10, L =20, C=30 Avg = 20
Probability = .1, .7, .4 = Avg probability = .03
IS 20*.03 same as .1*10 + .7*20 + .4*30 ------------NOOOOO
And that's the trap.... Ans E
COuntry X: Breakfast, Lunch in canteen(sugar ratio mentioned as twice of Y), dinner
Country Y Breakfast, Lunch in canteen(sugar ratio with X mentioned), dinner
Asked who eats more sugar. That will not just depend on lunch but other meals as well. Could be possible 'Y's breakfast and dinner is10 times sugar content of Breakfast and dinner. Also almost lunch is had by everyone - but on avg how much is tendency to skip breakfast or lunch - with this background lets make a formula Sugar content = Sugar in Breakfast*avg probability to have Breakfast
+ Sugar in Lunch*avg probability to have Lunch + Sugar in Dinner*avg probability to have Dinner.
Now
(1) For the average high schooler in Country Y, the average amount of sugar across all the meals of the day is similar to that contained in the AHCL in Country X.
We know avg sugar across the meal for 1 day not the probability to have. X could eat more likely in 1 day and Y could eat less. Weighted avgs - its not about what sugar content is present but consumed which is why probability to eat is imp
No
(2) In Country X, the average high schooler has one fewer meal per day compared with Country Y.
Well this answer's the second part I addressed in statement 1. Reject alone
Now together - I have avg of day and avg of probability but is this correct. Lets check mathematically
Sugar content B=10, L =20, C=30 Avg = 20
Probability = .1, .7, .4 = Avg probability = .03
IS 20*.03 same as .1*10 + .7*20 + .4*30 ------------NOOOOO
And that's the trap.... Ans E
