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15 Apr 2026, 19:00
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
81% (01:34) correct
19%
(02:19)
wrong
based on 57
sessions
History
Date
Time
Result
Not Attempted Yet
At the start of a data-conversion job, two servers, Alpha and Beta, were assigned to process the same batch of files. Both servers began processing at the same time, but Alpha was taken offline after 3 hours. Was the number of additional hours that Beta continued processing by itself before the entire batch was completed more than 3 hours?
(1) During the 3 hours that Alpha was running, it processed 1/3 of the batch.
(2) Beta would need 9 hours to process the entire batch by itself.
(1) During the 3 hours that Alpha was running, it processed 1/3 of the batch.
(2) Beta would need 9 hours to process the entire batch by itself.
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22 Apr 2026, 01:15
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GMAT Club Official Solution:
At the start of a data-conversion job, two servers, Alpha and Beta, were assigned to process the same batch of files. Both servers began processing at the same time, but Alpha was taken offline after 3 hours. Was the number of additional hours that Beta continued processing by itself before the entire batch was completed more than 3 hours?
(1) During the 3 hours that Alpha was running, it processed 1/3 of the batch.
Alpha handled 1/3 of the batch before going offline. That means Beta handled the other 2/3 of the batch. But knowing that Beta handled 2/3 of the work is still not enough, because we do not yet know how fast Beta processes files. Not sufficient.
(2) Beta would need 9 hours to process the entire batch by itself.
So this tells us Beta’s full-job time, but it does not tell us what share of the batch Beta actually processed in this situation. Not sufficient.
(1)+(2):
From (1), Beta processed 2/3 of the batch.
From (2), Beta needs 9 hours for the whole batch, so Beta needs 9 * 2/3 = 6 hours to process 2/3 of the batch.
Those 6 hours include the first 3 hours, because Beta was already working while Alpha was still online. So the time Beta worked alone was 6 - 3 = 3 hours. The answer to the question is no. Sufficient.
Answer: C
At the start of a data-conversion job, two servers, Alpha and Beta, were assigned to process the same batch of files. Both servers began processing at the same time, but Alpha was taken offline after 3 hours. Was the number of additional hours that Beta continued processing by itself before the entire batch was completed more than 3 hours?
(1) During the 3 hours that Alpha was running, it processed 1/3 of the batch.
Alpha handled 1/3 of the batch before going offline. That means Beta handled the other 2/3 of the batch. But knowing that Beta handled 2/3 of the work is still not enough, because we do not yet know how fast Beta processes files. Not sufficient.
(2) Beta would need 9 hours to process the entire batch by itself.
So this tells us Beta’s full-job time, but it does not tell us what share of the batch Beta actually processed in this situation. Not sufficient.
(1)+(2):
From (1), Beta processed 2/3 of the batch.
From (2), Beta needs 9 hours for the whole batch, so Beta needs 9 * 2/3 = 6 hours to process 2/3 of the batch.
Those 6 hours include the first 3 hours, because Beta was already working while Alpha was still online. So the time Beta worked alone was 6 - 3 = 3 hours. The answer to the question is no. Sufficient.
Answer: C
General Discussion
15 Apr 2026, 20:38
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Que: Was the total no of hours more than 3
Total work (Tw) not known = ?
From (1):
Take total work = 90 units in 3 hours.
Alpha does 1/3 of the work in 3 hours
→ 30 units in 3 hours
→ rate = 10 units/hour.
Expert replay requested
So, the other 2/3 work must be done by Beta right?
Similarly, Beta rate = 20 units/hour.
But Tw not given
Not sufficient.
From (2):
Beta alone takes 9 hours
Beta rate is not known
→ Tw not given
Not sufficient.
Combining:
Tw = Beta rate * 9 hr
=> 20 * 9
=> 180
Together for first 3 hours:
Combined rate
=> 20 + 10
=> 30 units/hour
=> 30* 3 = 90
=> Tw = 180 units.
So, 180-90 = 90 units left
Question: is this more than 3 hours?
Yes, it is more than 3 hours.
So, answer is Yes.
Both statements together are sufficient, neither alone is sufficient.
Answer: C
Total work (Tw) not known = ?
From (1):
Take total work = 90 units in 3 hours.
Alpha does 1/3 of the work in 3 hours
→ 30 units in 3 hours
→ rate = 10 units/hour.
Expert replay requested
So, the other 2/3 work must be done by Beta right?
Similarly, Beta rate = 20 units/hour.
But Tw not given
Not sufficient.
From (2):
Beta alone takes 9 hours
Beta rate is not known
→ Tw not given
Not sufficient.
Combining:
Tw = Beta rate * 9 hr
=> 20 * 9
=> 180
Together for first 3 hours:
Combined rate
=> 20 + 10
=> 30 units/hour
=> 30* 3 = 90
=> Tw = 180 units.
So, 180-90 = 90 units left
Question: is this more than 3 hours?
Yes, it is more than 3 hours.
So, answer is Yes.
Both statements together are sufficient, neither alone is sufficient.
Answer: C
