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Statement (1):
If 2 more food trucks had applied, the number of groups would have been 120.
(n + 2)C3 = 120
(n+2)(n+1)(n) / 6 = 120
(n+2)(n+1)(n) = 720
10 × 9 × 8 = 720
So, n = 8

Sufficient.

Statement (2):
(n-2)C3 = 20
(n-2)(n-3)(n-4) / 6 = 20
(n-2)(n-3)(n-4) = 120
6 × 5 × 4 = 120
So, n = 8

Sufficient.

Answer: D

Bunuel
A festival organizer is putting together the final set of food trucks for a weekend street-food event. Several food trucks applied, and exactly 3 of them will be chosen. How many different groups of 3 food trucks could be chosen?

(1) If 2 more food trucks had applied, the number of possible 3-truck groups would have been 120.
(2) If 2 fewer food trucks had applied, the number of possible 3-truck groups would have been 20.

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