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It can't be B. 5x+4=6,12,18,24, 30 ... solving those for x give some values of x that are divisible by 2, and some that are not.
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If x is positive is x divisible by 2 ?

(1) x^3+x is divisible by 4
(2) 5x+4 is divisible by 6
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Ans B.

A - x(x^2 +1)/4. whether x or x^2+1 is divisible by 4. cant say which.
B- (5x + 4)/6. x= 4, 16, ....divisible by 2.
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Answer C
Statement (2) alone is sufficient to answer.

Explaination -
For (1) X = Sqrt(3) or X=4

For (2) 5X+4 to be divisible by 6, X has to be an even integer >0 as 5X+4 should be even. So X will always be
divisible by 2

Oh Yes. 2 is not sufficient. Missed that X can be a fraction with a denominator of 5.

Answer c.
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If we can assume that x is an integer :

Is x even ?

From (1)

x^3 + x = 4k

x(x^2+1) = 4k

if x = Odd, then X^2 + 1 = even and is divisible by 2, but x is not divisible by 4, and X^2 + 1 needs one more 2 in its factor, which is not possible it it's odd. So x is even.

(Sufficient)

From (2)

5x + 4 = 6k

=> 5x + 4 has 2 and 3 as factors

So, 5x + 4 is even

so 5x + even = even

=> 5x = even

=> x = even

(sufficient)

Answer - D
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fluke,
I don't think above posters are correct. sqrt(3) is not a valid data for S1.
1.732*(4) is not divisible by 4.

1) x = 4. The answer is YES
x = 12 . The answer is YES
Sufficient.

2) Consider 5x = 14. 5x+4 = 18. The answer is NO
Consider 5x = 20. 5x+4 = 24. The answer is YES
Insufficient.

Hence A
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Quote:
If x is positive is x divisible by 2 ?

(1) x^3+x is divisible by 4
(2) 5x+4 is divisible by 6


x>0. is x a multiple of 2 (i.e. is x an even number)?

I got B for answer.
I am working based on the assumption that x is an integer, so that the question will be within the scope of GMAT..

Rules applied:
even + even = even
odd + even = odd
odd + odd = even
even * even = even
even * odd = even

Statement 1

x^3+x=4k ---> k being an integer
x(x^2+1)=4k

if x is even, (x^2+1) will be odd, multiplying both results in 4k (even).
if x is odd, (x^2+1) will be even, which also results in 4k (even)
--> insufficient

Statement 2
5x+4=6w ---> w being an integer
if x is even --> 5x will be even --> even + even = even --> results in even outcome i.e. 6w (true)
if x is odd --> 5x will be odd --> odd + even = odd --> results in odd outcome i.e. cannot be 6w
So x must be even.
--> sufficient

Answer: B
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