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Bunuel
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Bunuel
In a game with one die, player X wins if the number of points on her throw is greater than,or equal to, the number of points on player Y’s throw. The probability of X winning is:

(A) 1/2
(B) 19/36
(C) 13/24
(D) 7/12
(E) 2/3

Breaking Down the Info:

There are \(6 * 6 = 36\) outcomes in total.

The probability of X and Y tying, would be \(\frac{6}{36} = \frac{1}{6}\).

We can divide the rest of the probability space in half as the probability of X throwing higher than Y is the same as the probability of Y throwing higher than X.

Then the probability of X getting a higher throw is \(\frac{5}{6}/2 = \frac{5}{12}\). Finally add \(\frac{1}{6}\) back as a tie counts as X winning.

\(\frac{5}{12} + \frac{2}{12} = \frac{7}{12}\).

Answer: D
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Total no. of pairs of (x,y)=6*6=36

x>=y

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)=6 ways
(2,2), (2,3), (2,4), (2,5), (2,6)=5 ways
.
.
((6,6)=1 way

Similarly, we add up 6+5+4+3+2+1=21

Probability of x wining is =21/36=7/12
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