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saintforlife
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saintforlife
Solution:
I don't like drawing Venn diagrams because it is time consuming. I tend to use the formula:

(Total in Group 1) + (Total in Group 2) + (Total in Group 3) – (Overlap of 1 and 2) – (Overlap of 1 and 3) – (Overlap of 2 and 3) – [2 * (Overlap of 1, 2, and 3)] + (total in none of the groups) = Overall total

10 + 20 + 18 - 5 - 3 - 4 - 2(x) + 0 = 38.
=> 48 - 12 - 2x = 38
=> 36 - 2x = 38
=> x=-1

But the answer is:
X = 2

Where am I going wrong? I used the method suggested by Bunuel in this thread:
gmatclub dot com/forum/at-a-certain-resort-each-of-the-39-food-service-employees-133276.html

I agree that drawing venn diagram is a time taking thing. But you should be able to picturize the venn diagram in your mind to correctly understand the problem :)

As shown in the venn diagram below:
Attachment:
Venn_Diagram.png
Venn_Diagram.png [ 14.39 KiB | Viewed 23363 times ]

a = only action
b = only drama
c= only comedy

d = both action and drama but not comedy
e = both action and comedy but not drama
f = both drama and comedy but not action
g = all three

As per the question,
Both action and drama (including comedy) = d + g = 5
Both action and comedy (including drama) = e + g = 3
Both drama and comedy (including action) = f + g = 4

Action = a + d + g + e = 10
Drama = b + d + f + g = 20
Comedy = c + e + f + g = 18

As per your formula:
(Total in Action) + (Total in Drama) + (Total in Comedy) – (Overlap of A and D) – (Overlap of D and C) – (Overlap of A and C) – [2 * (Overlap of A, D, and C)] + (total in none of the groups) = Overall total
=> (a + d + g + e) + (b + d + f + g) + (c + e + f + g) – (d + g) – (e + g) – (f + g) – (2*g) + 0 = 38

Here you can see that you are adding g thrice but subtraction g 5 times (3 + 2)
So instead of subtracting 2g, you have to add “g” once as you have already added g thrice and subtracted thrice earlier

Hence the correct formula should be:
(a + d + g + e) + (b + d + f + g) + (c + e + f + g) – (d + g) – (e + g) – (f + g) + (g) + 0 = 38
=> 10 + 20 + 18 - 5 - 3 – 4 + g = 38
=> 48 – 12 + g = 38
=> 36 + g = 38
=> g = 38 – 36 = 2
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The 38 movies in the video store fall into the following three categories: 10 action; 20 drama; 18 comedy
5 are both action and drama; 3 are both action and comedy; 4 are both drama and comedy
How many action-drama-comedies are there?

38=10+20+18-5-3-4
38=36
38-36=ADC

Answer -> 2
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Bunuel KarishmaB


What about the well known formula for the union of all three.

Let X be the number of movies in all three section (the inner-most)


10+20+18-(12+2X)=38 the 12 is the sum of the movies that are in two catogories(5+4+3=12)


10+20+18-(12+2X)=38

48-12-2X=38

36-2X=38

2X=-2

X=-1, which does not make sense.

Where am i going wrong? How is it possible that most often to find the inner most is the above approach correct but not for this question.
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Rebaz
Bunuel KarishmaB


What about the well known formula for the union of all three.

Let X be the number of movies in all three section (the inner-most)


10+20+18-(12+2X)=38 the 12 is the sum of the movies that are in two catogories(5+4+3=12)


10+20+18-(12+2X)=38

48-12-2X=38

36-2X=38

2X=-2

X=-1, which does not make sense.

Where am i going wrong? How is it possible that most often to find the inner most is the above approach correct but not for this question.

There are two formulae and you are using the wrong one. Check here: https://gmatclub.com/forum/the-38-movie ... 60697.html

Hope it helps.
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brunel
If I use the first formula:

x = group overlaps/all three

Total=A+B+C−(sum of 2−group overlaps)+(all three)+Neither
=> 38 = 10 + 18 + 20 - (5 + 4 + 3 - (x)) + x
=> 2 = 2x
=> x = 1

What is wrong in this?
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brunel
If I use the first formula:

x = group overlaps/all three

Total=A+B+C−(sum of 2−group overlaps)+(all three)+Neither
=> 38 = 10 + 18 + 20 - (5 + 4 + 3 - (x)) + x
=> 2 = 2x
=> x = 1

What is wrong in this?

You don't need to subtract x. Please study this: https://gmatclub.com/forum/advanced-ove ... 44260.html
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Bunuel
The 38 movies in the video store fall into the following three categories: 10 action, 20 drama, and 18 comedy. However, some movies are classified under more than one category: 5 are both action and drama, 3 are both action and comedy, and 4 are both drama and comedy. How many action-drama-comedies are there?

A. 1
B. 2
C. 3
D. 4
E. 5


{Total} = {action} + {drama} + {comedy} - {action&drama + action&comedy + drama&comedy} + {action&drama&comedy}

38 = 10 + 20 + 18 -(5 + 3 + 4) + {action&drama&comedy}

{action&drama&comedy} = 2.

ADVANCED OVERLAPPING SETS PROBLEMS: https://gmatclub.com/forum/advanced-ove ... 44260.html

Hope it helps.
I am confused regarding the formula...
on other questions you have mentioned this formula as T = A+B+C - (in exactly 2) - 2*(in exactly 3)
but here you have mentioned the formula as T = A+B+C - (in exactly 2) + (in exactly 3)
my doubt is when to use what formula
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voluptatemfuga

I am confused regarding the formula...
on other questions you have mentioned this formula as T = A+B+C - (in exactly 2) - 2*(in exactly 3)
but here you have mentioned the formula as T = A+B+C - (in exactly 2) + (in exactly 3)
my doubt is when to use what formula

Explained here ADVANCED OVERLAPPING SETS PROBLEMS: https://gmatclub.com/forum/advanced-ove ... 44260.html
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