There are 68 cars on a parking lot. If 36 of the cars are sedans, and

Question

There are 68 cars on a parking lot. If 36 of the cars are sedans, and 48 of the cars have automatic transmissions, what is the ratio of the minimum possible number of sedans with automatic transmissions to the number of cars in the parking lot?

A. 3:17
B. 4:17
C. 5:17
D. 6:17
E. 4:19

A. 3:17
B. 4:17
C. 5:17
D. 6:17
E. 4:19

vijayram2496 · Answer

Min number of cars with Sedan = 16
Total = 68
Ratio = 4/17

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Sr1994 · Answer

We need to get the ratio of   number of sedans with automatic transmissions to the number of cars in the parking lot

the number of sedans with automatic transmissions is shown in the image with orange colour.

To get the minimum value, we need the number of manual sedan cars to be maximum. 
To get the maximum value for manual sedan cars, we need to make manual non-sedan cars to be minimum. Thus if we give 0 to manual non-sedan cars.

Then Automatic Sedan cars = 36 - 20 = 16

Then ratio = 16:68 =  4:17

Answer B

zoey09 · Answer

Here's my 2 cents on this:
1. to have min #sedans with AT => you need to max #sedans with no AT.
2. Total No AT cars = Total - #AT cars = 20 => all of these should be sedans
3. Then you have your min #sedans with AT = 36-20 = 16
4. Your min ratio = 16/68 = 4/17
Hope it is clear and helpful

ScottTargetTestPrep · Answer

We can create the equation:

68 = 36 + 48 - both + neither

We need to minimize “both.”

SImplifying we have:

68 = 84 - both + neither

Both - neither = 16

So to minimize “both,” we make neither 0, so both = 16.

Thus, the ratio is:

16/68 = 8/34 = 4/17

Answer: B

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There are 68 cars on a parking lot. If 36 of the cars are sedans, and

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There are 68 cars on a parking lot. If 36 of the cars are sedans, and

Prep Toolkit

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