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10 Oct 2019, 02:20
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
74% (00:58) correct
26%
(01:10)
wrong
based on 39
sessions
History
Date
Time
Result
Not Attempted Yet
Is \(x^2 > x\)?
(1) \(x^2 > 1\)
(2) \(x > -1\)
(1) \(x^2 > 1\)
(2) \(x > -1\)
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
firas92
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GMAT 1: 740 Q50 V40
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10 Oct 2019, 05:36
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Is \(x^2>x?\)
Is \(x^2-x>0?\)
Is \(x(x-1)>0?\)
If \(x(x-1)>0\), then
Case 1. \(x>0\) and \(x-1>\)0, or
\(x>0\) and \(x>1\) which is
\(x>1\)
Case 2. \(x<0\) and \(x-1<0\)
\(x<0\) and \(x<1\) which is
\(x<0\)
Therefore, when \(x(x-1)>0\), either \(x>1\) or \(x<0\)
(1) \(x^2>1\)
This means, \(x>1\) or \(x<-1\)
In both cases \(x(x-1)>0\)
1 is sufficient
(2) \(x>−1\)
If \(x>1\), \(x(x-1)>0\)
If \(0<x<1\), \(x(x-1)<0\)
2 is insufficient
Answer is (A)
Is \(x^2-x>0?\)
Is \(x(x-1)>0?\)
If \(x(x-1)>0\), then
Case 1. \(x>0\) and \(x-1>\)0, or
\(x>0\) and \(x>1\) which is
\(x>1\)
Case 2. \(x<0\) and \(x-1<0\)
\(x<0\) and \(x<1\) which is
\(x<0\)
Therefore, when \(x(x-1)>0\), either \(x>1\) or \(x<0\)
(1) \(x^2>1\)
This means, \(x>1\) or \(x<-1\)
In both cases \(x(x-1)>0\)
1 is sufficient
(2) \(x>−1\)
If \(x>1\), \(x(x-1)>0\)
If \(0<x<1\), \(x(x-1)<0\)
2 is insufficient
Answer is (A)
10 Oct 2019, 21:53
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Here the question asks is \(x^2 > x\)?
We know that i) if \(0<x<1\) then \(x^2< x\) and ii) if \(x>1\) or \(x<-1\) then \(x^2 > x\)
So, all we need to find out is \(x>1\) or \(x<-1\)?
Let's look at the statements
1) \(x>1\) - this statement clearly states what we are looking for hence sufficient \(x^2 > x\)
2) \(x>-1\) this could mean \(-1<x<0\) or \(0<x<1\) or \(x>1\) hence not sufficient
Statement 1 alone is sufficient while Statement 2 is not sufficient
Answer [A]
We know that i) if \(0<x<1\) then \(x^2< x\) and ii) if \(x>1\) or \(x<-1\) then \(x^2 > x\)
So, all we need to find out is \(x>1\) or \(x<-1\)?
Let's look at the statements
1) \(x>1\) - this statement clearly states what we are looking for hence sufficient \(x^2 > x\)
2) \(x>-1\) this could mean \(-1<x<0\) or \(0<x<1\) or \(x>1\) hence not sufficient
Statement 1 alone is sufficient while Statement 2 is not sufficient
Answer [A]
