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31 Aug 2020, 00:13
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
77% (01:04) correct
23%
(01:13)
wrong
based on 232
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Not Attempted Yet
Mr. Mike took a two-day automobile trip. What was her average speed in kilometers per hour while driving?
(1) She drove 300 killmeters the first day and 267 killometers the second day.
(2) She drove exactly one hour longer the first day than she did the second day.
(1) She drove 300 killmeters the first day and 267 killometers the second day.
(2) She drove exactly one hour longer the first day than she did the second day.
yashikaaggarwal
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31 Aug 2020, 00:50
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Average speed = \(\frac{Total distance}{Total time taken}\)
(1) She drove 300 killmeters the first day and 267 killometers the second day.
Neither Speed nor time is given (insufficient)
(2) She drove exactly one hour longer the first day than she did the second day.
Distance is not given..
(Insufficient)
Combining both: \(\frac{Total Distance}{Total time taken}\) = Average Speed.
\(567/\)\(\frac{300}{t}\)+\(\frac{267}{t+1}\)= Average speed.
\(567/\)\(\frac{(300t + 300)+267t}{t^2+t}\) = Average speed.
\(\frac{567t^2+567t}{567t+300}\)
We have no further equation of constraint to solve for t.
(Insufficient)
Answer is E
Posted from my mobile device
(1) She drove 300 killmeters the first day and 267 killometers the second day.
Neither Speed nor time is given (insufficient)
(2) She drove exactly one hour longer the first day than she did the second day.
Distance is not given..
(Insufficient)
Combining both: \(\frac{Total Distance}{Total time taken}\) = Average Speed.
\(567/\)\(\frac{300}{t}\)+\(\frac{267}{t+1}\)= Average speed.
\(567/\)\(\frac{(300t + 300)+267t}{t^2+t}\) = Average speed.
\(\frac{567t^2+567t}{567t+300}\)
We have no further equation of constraint to solve for t.
(Insufficient)
Answer is E
Posted from my mobile device
Archit3110
Major Poster
31 Aug 2020, 00:53
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Bunuel
target find total distance / total time = avg speed
#1
She drove 300 killmeters the first day and 267 killometers the second day.
speed of both days not know insufficient
#2
She drove exactly one hour longer the first day than she did the second day.
day 2 be x hrs
time day 1; x +1 hrs
insufficient as distance is not know
from 1 &2
we get
300/x+1 + 267/x
but value of x is not know insufficiet
OPTION E ;
