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Bunuel
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Bunuel

Tough and Tricky questions: Geometry Problems.



How many bags of grass seed were used for rectangular lawn X ?

(1) Lawn X has a perimeter of 240 feet.
(2) One bag of grass seed was used for each 5,000 square feet of lawn X

Kudos for a correct solution.

We need to find the area of the rectangular

1. 2(l+b) = 240=> l+b = 120
l+b = 120
b=120-l
area = lb=l(l-120)=l^2 - 120l Not Sufficient

2. Not sufficient as it does not address the area of the rectangular


Combining both - Still area is unknown - So not sufficient

Ans (E)
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Bunuel

Tough and Tricky questions: Geometry Problems.



How many bags of grass seed were used for rectangular lawn X ?

(1) Lawn X has a perimeter of 240 feet.
(2) One bag of grass seed was used for each 5,000 square feet of lawn X

Kudos for a correct solution.

We need to find the area of the rectangular

1. 2(l+b) = 240=> l+b = 120
l+b = 120
b=120-l
area = lb=l(l-120)=l^2 - 120l Not Sufficient

2. Not sufficient as it does not address the area of the rectangular


Combining both - Still area is unknown - So not sufficient

Ans (E)

I am afraid thats not entirely true Combining both Stats 1 & 2 you do know that the Max Area can be both L=B=60 then Area=3600 and that is still less than 5000 sq meter which can be easily covered using 1 bag full of seeds so no matter what we require 1 bag only so both Stats are sufficient to Answer so C has to be answer.



Thanks
Ak
Please press Kudos for Appreciation :-D
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Bunuel

Tough and Tricky questions: Geometry Problems.



How many bags of grass seed were used for rectangular lawn X ?

(1) Lawn X has a perimeter of 240 feet.
(2) One bag of grass seed was used for each 5,000 square feet of lawn X

Kudos for a correct solution.

We need to find the area of the rectangular

1. 2(l+b) = 240=> l+b = 120
l+b = 120
b=120-l
area = lb=l(l-120)=l^2 - 120l Not Sufficient

2. Not sufficient as it does not address the area of the rectangular


Combining both - Still area is unknown - So not sufficient

Ans (E)

I am afraid thats not entirely true Combining both Stats 1 & 2 you do know that the Max Area can be both L=B=60 then Area=3600 and that is still less than 5000 sq meter which can be easily covered using 1 bag full of seeds so no matter what we require 1 bag only so both Stats are sufficient to Answer so C has to be answer.



Thanks
Ak
Please press Kudos for Appreciation :-D


I missed that... Thanks for correcting it :-)
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Bunuel

Tough and Tricky questions: Geometry Problems.



How many bags of grass seed were used for rectangular lawn X ?

(1) Lawn X has a perimeter of 240 feet.
(2) One bag of grass seed was used for each 5,000 square feet of lawn X

Kudos for a correct solution.

The correct answer is C.
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Assume length is L and breadth is b for rectangle X.

S(1): Perimeter is 240. ==> 2(l+b)=240 ==> (L+B)= 120. This give no information about seeds. Hence Not Suff.

S(2): 5000 Square feet would require 1 bag of seed. No information regarding area of rectangle. Hence no relation. Thus not sufficient.

Combining: From statement 1 we know L+B=120. We also know that L.B will be maximum when L=B. If we consider that then 2L=120 ==> L=60. Thus maximum area of rectangle is L*B=60*60= 3600 Sq units. Since we are given that 5000 Sq units require 1 packet and as rectangle will never have area more than 3600 sq units required quanity of seed packet is 1.

Thus answer is C.
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