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04 Dec 2020, 06:30
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
77% (01:52) correct
23%
(02:17)
wrong
based on 195
sessions
History
Date
Time
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Not Attempted Yet
A solution is 90% glycerin. If there are 4 gallons of the solution, how much water, in gallons must be added to make a 75% glycerin solution?
A. 1.8
B. 1.4
C. 1.2
D. 1.0
E. 0.8
A. 1.8
B. 1.4
C. 1.2
D. 1.0
E. 0.8
07 Dec 2020, 06:30
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Bunuel
In 4 gallons of the solution there are \(0.9*4=3.6\) gallons of glycerin. We want to add \(w\) gallons of water to 4 gallons of solution so that these 3.6 gallons of glycerin to be 75% of new solution: \(0.9*4=0.75(4+w)\) --> \(w=0.8\)
Answer: E.
General Discussion
04 Dec 2020, 09:23
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IMO E
Given the ratio of G:W in the solution which is 4 gallons, try to form the equation in terms of the quantity which needs to be found out instead of the quantity that is given - it makes calculations simpler and faster.
We know that the percentage of water in the original solution is 10%, hence we can calculate the volume.
Assuming 'x' gallons of water needs addition.
Then,
2/5 + x=1/4(4+x)
x-x/4=1-2/5
3x/4=3/5
x=0.8
Given the ratio of G:W in the solution which is 4 gallons, try to form the equation in terms of the quantity which needs to be found out instead of the quantity that is given - it makes calculations simpler and faster.
We know that the percentage of water in the original solution is 10%, hence we can calculate the volume.
Assuming 'x' gallons of water needs addition.
Then,
2/5 + x=1/4(4+x)
x-x/4=1-2/5
3x/4=3/5
x=0.8
