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20 Mar 2025, 01:34
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
81% (02:28) correct
19%
(02:48)
wrong
based on 67
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An electronics salesman earned a x% commission on each of the m digital music player he sold in the month of March at the retail price of $p each. In April, he earned a y% commission on sales of the same item, and the price remained the same. If y > x and he sold q more digital music players in April than in March, how much more money did he earn selling digital music players in April than in March?
(A) \(\frac{p}{100} (ym - x(m + q))\)
(B) \(\frac{p}{100} (x(m + q) + ym)\)
(C) \(p(y(m - q) - xm)\)
(D) \(\frac{p}{100}(x(m + q) - ym)\)
(E) \(\frac{p}{100} (y(m + q) - xm)\)
(A) \(\frac{p}{100} (ym - x(m + q))\)
(B) \(\frac{p}{100} (x(m + q) + ym)\)
(C) \(p(y(m - q) - xm)\)
(D) \(\frac{p}{100}(x(m + q) - ym)\)
(E) \(\frac{p}{100} (y(m + q) - xm)\)
20 Mar 2025, 01:39
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Bunuel
(x/100)*mp
(y/100)*(m+q)p
Difference of money = (y/100)*(m+q)p - (x/100)*mp = (p/100)*[y(m + q) - xm]
Answer: Option E
Bunuel: Correction in language. First highlight part should have a word each and second one should be same and not sale
Related Video:
20 Mar 2025, 05:27
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For March:
No. of digital music players sold = m
Cost of 1 music player = p
Commission = x% i.e. \(\frac{x}{100}\)
Therefore the money he earned in March will be \(\frac{(m*p*x)}{100}\)
For April:
No. of digital music players sold = m+q (As he sold q more music players than sold in March i.e. m)
Cost of 1 music player = p
Commission = y% i.e. \(\frac{y}{100}\)
Therefore the money he earned in April will be \(\frac{(m+q)*p*y}{100.}\)
(Note: As he earned commission on the number of music players sold, hence it will be x% of m*p and y% of p*(m+q))
More money earned by selling music players in April than in march would simply be the difference of the two.
\(\frac{p*(m+q)*y}{100}\) - \(\frac{p*m*x}{100}\)
Taking \(\frac{p}{100}\) common,
\(\frac{p}{100}(y(m+q)) - mx)\)
Which is Answer Choice E.
P.S.: Do correct me if the answer is incorrect
Thanks!
No. of digital music players sold = m
Cost of 1 music player = p
Commission = x% i.e. \(\frac{x}{100}\)
Therefore the money he earned in March will be \(\frac{(m*p*x)}{100}\)
For April:
No. of digital music players sold = m+q (As he sold q more music players than sold in March i.e. m)
Cost of 1 music player = p
Commission = y% i.e. \(\frac{y}{100}\)
Therefore the money he earned in April will be \(\frac{(m+q)*p*y}{100.}\)
(Note: As he earned commission on the number of music players sold, hence it will be x% of m*p and y% of p*(m+q))
More money earned by selling music players in April than in march would simply be the difference of the two.
\(\frac{p*(m+q)*y}{100}\) - \(\frac{p*m*x}{100}\)
Taking \(\frac{p}{100}\) common,
\(\frac{p}{100}(y(m+q)) - mx)\)
Which is Answer Choice E.
P.S.: Do correct me if the answer is incorrect
Thanks!
Bunuel
