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Sub 505 (Easy)|   Algebra|                           
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If x > 3,000, then the value of x/(2x+ 1) is closest to

(A) 1/6
(B) 1/3
(C) 10/21
(D) 1/2
(E) 3/2


Let us say x = 3999.5 then 3999.5/(8000)

Now we approximate = 4000/8000 = 1/2
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1 is very less as compared to 3000 so the effect of adding 1 to denominator is negligible . By approximation we can say that it will be always closest to 1/2. Another way can be differential calculus.
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Question ask to approximate x/(2x+1) when x>3000
x/(2x+1), you can ignore the 1 because the value is too small when x>3000.
x/2x. x cancels out
1/2. Answer choice D.
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This is another logic problem...because \(x>3000\) its clear that adding \(1\) to \(6000\) creating a number like \(\frac{3001}{6002+1}\) is close to \(\frac{3001}{6002}\) or \(\frac{1}{2}\)

Little to no math involved

ALL LOGIC
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cloaked_vessel
If x > 3000, then the value of (x)/(2x+1) is closest to?

A. 1/6
B. 1/3
C. 10/21
D. 1/2
E. 3/2

Let’s say x = 3001; we have:

3001/(6002 + 1), which is about 3,000/6,000 = 1/2.

Answer: D
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Since 1 is negligible in compare to 3000 then we get 3000/6000 = 1/2
{D}
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Bunuel
If x > 3,000, then the value of x/(2x + 1) is closest to

(A) 1/6
(B) 1/3
(C) 10/21
(D) 1/2
(E) 3/2

Problem Solving
Question: 42
Category: Algebra Simplifying algebraic expressions
Page: 67
Difficulty: 600

The Official Guide For GMAT® Quantitative Review, 2ND Edition

Let \(x = 301\)

So, \(\frac{x}{(2x + 1)} = \frac{301}{(2*301 + 1)} = \frac{301}{603}\) ~ \(\frac{301}{602} = \frac{1}{2}\), Answer must be (D)
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Bunuel
If x > 3,000, then the value of x/(2x + 1) is closest to

(A) 1/6
(B) 1/3
(C) 10/21
(D) 1/2
(E) 3/2





Nick Slavkovich, GMAT/GRE tutor with 20+ years of experience

[email protected]
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