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danzig
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A square is inscribed in a circle whose area is 18 23 Mar 2014, 18:21
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95% (hard)

Question Stats:

31% (02:17) correct 69% (01:41) wrong based on 26 sessions

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A square is inscribed in a circle whose area is 18. Please, find the lenght of the square.

A. 3
B. 6
C. \(3\sqrt{2}\)
D. \(6\sqrt{2}\)
E. None of above

I think this question is totally wrong :s . Please, your help.

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Bunuel
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A square is inscribed in a circle whose area is 18 24 Mar 2014, 01:15
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danzig
A square is inscribed in a circle whose area is 18. Please, find the lenght of the square.

A. 3
B. 6
C. \(3\sqrt{2}\)
D. \(6\sqrt{2}\)
E. None of above

I think this question is totally wrong :s . Please, your help.
Show more

I guess the question asks to find the length of a side of the square.

The area of the circle is 18 square units: \(area=\pi{r^2}=18\) --> \(r=\frac{3\sqrt{2}}{\sqrt{\pi}}\).

Now, when a square is inscribed in a circle, the diameter of the circle becomes the diagonal of the square.

The diagonal of the square = \(side=\frac{diagonal}{\sqrt{2}}=\frac{diameter}{\sqrt{2}}=\frac{(2\frac{3\sqrt{2}}{\sqrt{\pi}})}{\sqrt{2}}=\frac{6}{\sqrt{\pi}}\).

What is the source of the question? What is the exact wording of the question?
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samirchaudhary
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A square is inscribed in a circle whose area is 18 24 Mar 2014, 06:35
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For the given answer i.e 6 to be correct, area of the circle has to be 18 \pi
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A square is inscribed in a circle whose area is 18 24 Mar 2014, 20:56
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Bunuel
danzig
A square is inscribed in a circle whose area is 18. Please, find the lenght of the square.

A. 3
B. 6
C. \(3\sqrt{2}\)
D. \(6\sqrt{2}\)
E. None of above

I think this question is totally wrong :s . Please, your help.

I guess the question asks to find the length of a side of the square.

The area of the circle is 18 square units: \(area=\pi{r^2}=18\) --> \(r=\frac{3\sqrt{2}}{\pi}\).

Now, when a square is inscribed in a circle, the diameter of the circle becomes the diagonal of the square.

The diagonal of the square = \(side=\frac{diagonal}{\sqrt{2}}=\frac{diameter}{\sqrt{2}}=\frac{(2\frac{3\sqrt{2}}{\pi})}{\sqrt{2}}=\frac{6}{\pi}\).

What is the source of the question? What is the exact wording of the question?
Show more


Hello Bunuel

Given : Area of the Circle is 18 Sq Units : \(area=\pi{r^2}=18\) --> \({r^2}=18/\pi\)

Then Souldnt it be :\(r=\frac{3\sqrt{2}}{\sqrt{{\pi}}}\).

& Not \(r=\frac{3\sqrt{2}}{\pi}\).
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A square is inscribed in a circle whose area is 18 25 Mar 2014, 02:26
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niyantg
Bunuel
danzig
A square is inscribed in a circle whose area is 18. Please, find the lenght of the square.

A. 3
B. 6
C. \(3\sqrt{2}\)
D. \(6\sqrt{2}\)
E. None of above

I think this question is totally wrong :s . Please, your help.

I guess the question asks to find the length of a side of the square.

The area of the circle is 18 square units: \(area=\pi{r^2}=18\) --> \(r=\frac{3\sqrt{2}}{\pi}\).

Now, when a square is inscribed in a circle, the diameter of the circle becomes the diagonal of the square.

The diagonal of the square = \(side=\frac{diagonal}{\sqrt{2}}=\frac{diameter}{\sqrt{2}}=\frac{(2\frac{3\sqrt{2}}{\pi})}{\sqrt{2}}=\frac{6}{\pi}\).

What is the source of the question? What is the exact wording of the question?


Hello Bunuel

Given : Area of the Circle is 18 Sq Units : \(area=\pi{r^2}=18\) --> \({r^2}=18/\pi\)

Then Souldnt it be :\(r=\frac{3\sqrt{2}}{\sqrt{{\pi}}}\).

& Not \(r=\frac{3\sqrt{2}}{\pi}\).
Show more

Yes. Formatting issue. Typo edited. Thank you.

Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
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