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russ9
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russ9
Hi,

I've posted an image of a problem I encountered. Unfortunately, I don't have the answer choices but I was wondering if you could help me out?

Thanks!

Similar question: as-shown-in-figure-square-abcd-has-arc-bpd-centred-at-c-and-arc-bqd-181218.html

Check other Shaded Region Problems in our Special Questions Directory.
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russ9
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russ9
Hi,

I've posted an image of a problem I encountered. Unfortunately, I don't have the answer choices but I was wondering if you could help me out?

Thanks!

Similar question: as-shown-in-figure-square-abcd-has-arc-bpd-centred-at-c-and-arc-bqd-181218.html

Check other Shaded Region Problems in our Special Questions Directory.

Great. Thanks -- similar to what the above poster was saying. The visual helps!
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russ9
Hi,

I've posted an image of a problem I encountered. Unfortunately, I don't have the answer choices but I was wondering if you could help me out?

Thanks!


The above figure can be divided into two Sectors.

Area of Sector = (Angle / 360)*Pi*R^2

Area of Sector = (90/360)*Pi*1 = 1/4Pi

Therefore area of Both Sectors = 2*(1/4)Pi = (1/2)*Pi ---------------------- {The two sectors will be equal in Area}

Now Area of Shaded Region= Area of both Sectors - Area of square
Area of Shaded Region = 1/2Pi - 1

Therefore,
Area of Unshaded Region = Area of Square - Area of shaded region
Area of Unshaded Region = 1-1/2Pi +1
Area of Unshaded Region = 2- (1/2) Pi


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