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Please explain the OS for the question.
i too got C as answer
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Let total # of games be T.
As of now, # of games played = x% of T = xT/100
As of now, # of games Won = 40% of xT/100 = 40xT/(100*100)

minimum percentage of games the lions could have won at the end of the season is when they loose all the rest of the games

So at the end of the season, # of games played = T
So at the end of the season, # of games won = 40xT/(100*100)

% of games won at the end of the season = (40xT/(100*100) * 100 )/T = 40x/100

Hence Ans = C

Bunuel , every one seems to be getting the same ans, C. Can you please provide the explanation for the OA.
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Bunuel
After x% of their games had been played, the Lions had won 40%of their games. In terms of x, which of the following expresses the minimum percentage of games the lions could have won at the end of the season?

A. 40x %
B. 60x/100 %
C. 40x/100 %
D. 20x/100 %
E. 10x/100 %

Hi Bunuel,
the answer seems to be C solving by algebrically or by substitution..
Pl relook into it...



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