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Bunuel
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Eleven animals of a circus has to be placed inside in eleven cages one 13 Feb 2020, 07:24
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C
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55% (hard)

Question Stats:

65% (02:47) correct 35% (02:56) wrong based on 102 sessions

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Eleven animals of a circus has to be placed inside in eleven cages one in each cage. If 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal.

A. 808,250
B. 784,200
C. 604,800
D. 502,450
E. 302,400
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C
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Eleven animals of a circus has to be placed inside in eleven cages one 13 Feb 2020, 19:46
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we have 6 big animals who are to be caged in 7 cages ; total ways 7!
and 5 small animals who are to be caged in 4 cages ; 5! ways
total 7!*5! ; 604800
IMO C


Bunuel
Eleven animals of a circus has to be placed inside in eleven cages one in each cage. If 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal.

A. 808,250
B. 784,200
C. 604,800
D. 502,450
E. 302,400
Show more
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Eleven animals of a circus has to be placed inside in eleven cages one 17 Feb 2020, 23:45
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Archit3110
we have 6 big animals who are to be caged in 7 cages ; total ways 7!
and 5 small animals who are to be caged in 4 cages ; 5! ways
total 7!*5! ; 604800
IMO C


Bunuel
Eleven animals of a circus has to be placed inside in eleven cages one in each cage. If 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal.

A. 808,250
B. 784,200
C. 604,800
D. 502,450
E. 302,400
Show more


How 5 animals can be caged in 4 cages ? , if we have 5 numbers and 5 places we can say 5! , are u counting the remaining space left in arranging of big animals ? , please clarify
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Eleven animals of a circus has to be placed inside in eleven cages one 03 Apr 2020, 01:39
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The 6 animals who are too big for the 4 cages will have to be caged in the remaining 7 "big" cages.

The number of ways of doing this:
= C (7,6) * 6! (Since they can be caged in any sequence)

Remaining 5 animals will have to be caged in the 4 "small" cages + 1 "big" remaining cage.

The number of ways of caging these 5 animals in the 5 cages:
= 5!

Total number of ways:
= C(7,6) * 6! * 5!
= 7! * 5!
= 604,800

IMO, answer: C
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Eleven animals of a circus has to be placed inside in eleven cages one 03 Apr 2020, 02:42
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BhishmaNaidu99
Archit3110
we have 6 big animals who are to be caged in 7 cages ; total ways 7!
and 5 small animals who are to be caged in 4 cages ; 5! ways
total 7!*5! ; 604800
IMO C


Bunuel
Eleven animals of a circus has to be placed inside in eleven cages one in each cage. If 4 of the cage are too small for 6 of the animal then find the number of ways of caging the animal.

A. 808,250
B. 784,200
C. 604,800
D. 502,450
E. 302,400


How 5 animals can be caged in 4 cages ? , if we have 5 numbers and 5 places we can say 5! , are u counting the remaining space left in arranging of big animals ? , please clarify
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He got lucky with the math here. you have 5 options but need to choose 4 so the calculation is 5*4*3*2 (if you have 5 options for 5 choices you get 5*4*3*2*1=5!)
For example, if you have 6 animals for 4 cages you get 6*5*4*3 and not 6! that is why I say he got lucky that the result was correct haha
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Eleven animals of a circus has to be placed inside in eleven cages one 03 Apr 2020, 02:45
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DUtkarsh
The 6 animals who are too big for the 4 cages will have to be caged in the remaining 7 "big" cages.

The number of ways of doing this:
= C (7,6) * 6! (Since they can be caged in any sequence)

Remaining 5 animals will have to be caged in the 4 "small" cages + 1 "big" remaining cage.

The number of ways of caging these 5 animals in the 5 cages:
= 5!

Total number of ways:
= C(7,6) * 6! * 5!
= 7! * 5!
= 604,800

IMO, answer: C
Show more

You should start with the restricting factor. If you have 3 or 4 options with restrictions and you start with the option that doesnt have a restriction (the big cage) your calculation can be wrong. Better be safe and start calculating from the restricting option. It is fortunate that here we have only 2 options but your mindset should be the same for easy and difficult problems in order to not get stuck during the GMAT
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Eleven animals of a circus has to be placed inside in eleven cages one 18 Jul 2024, 09:46
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