Two workers A and B are engaged to do a work. A working alone takes 8

Question

Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours

Are You Up For the Challenge: 700 Level Questions

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours

Are You Up For the Challenge: 700 Level Questions

Abhishek009 · Accepted Answer

A short little formula exists which can solve it in 10 secs -

\sqrt{8*4.5}

= \sqrt{36}

= 6  , Answer must be (C)

firas92 · Answer

(A+B)t=1  or  (A+B)=\frac{1}{t} 
 A(t+8)=1  or  A=\frac{1}{t+8} 
 B(t+4.5)=1  or  B=\frac{1}{t+4.5}

\frac{1}{t+8}+\frac{1}{t+4.5}=\frac{1}{t}

\frac{1}{t+4.5}=\frac{1}{t}-\frac{1}{t+8}

\frac{1}{t+4.5}=\frac{t+8-t}{t(t+8)}

t(t+8)=8(t+4.5)

t^2+8t=8t+36

t^2=36

t=6

Answer is  (C)

sujoykrdatta · Answer

Question: 
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together?

Solution: 
Let A and B together take t hours to complete the work. 
Thus, time taken by A = (t + 8) hrs and time taken by B = (t + 4.5) hrs

Thus, we can say that: 
 Work done by (A and B) in t hours = Work done by A in (t + 8) hours = Total work

=> (Work done by A in t hrs) + (Work done by B in t hrs) = (Work done by A in t hrs) + (Work done by A in 8 hrs)

Cancelling the (Work done by A in t hrs) from both sides: 
(Work done by B in t hrs) = (Work done by A in 8 hrs)

=>  Work done by B in 1 hr = Work done by A in (8/t) hrs  ... (i)

Similarly, we have: 
 Work done by (A and B) in t hours = Work done by B in (t + 4.5) hours = Total work 
=> (Work done by A in t hrs) + (Work done by B in t hrs) = (Work done by B in t hrs) + (Work done by B in 4.5 hrs)

Cancelling the (Work done by B in t hrs) from both sides: 
(Work done by A in t hrs) = (Work done by B in 4.5 hrs)
=>  Work done by B in 1 hr = Work done by A in (t/4.5) hrs  ... (ii)

Thus, from (i) and(ii):

8/t = t/4.5

=>  t^2 = 36 
=> t = 6 hrs

Answer C

Alternate approach 
Let time taken by A and B together be t hours
Thus, time taken by A = (t + 8) hrs and time taken by B = (t + 4.5) hrs

thus, equating work done by A and B in 1 hour: 
1/(t + 8) + 1/(t + 4.5) = 1/t

Solving, we get: t = 6 hours
 Answer C

exc4libur · Answer

r=w/t

(a+b)=1/t
a=1/t+8
b=1/t+4.5
(1/t+8)+(1/t+4.5)=1/t
2t^2+12.5t=t^2+12.5t+36
t^2=36 (t>0) t=6

Ans (C)

TheNightKing · Answer

Abhishek009

Any theory or links on how this is achievable and in what conditions it usually works?

Thank you!

ScottTargetTestPrep · Answer

Let’s let n = the number of hours it takes to complete the job when A and B work together; thus, their combined rate is 1/n. Since A alone takes 8 hours more than if they work together, then A’s rate is 1/(n + 8). And since B alone takes 4.5 hours more than if they work together, then B’s rate is 1/(n + 4.5).

Thus, , we can create the rate equation:

1/(n + 8) + 1/(n + 4.5) = 1/n

Multiplying by n(n + 8)(n + 4.5), we have:

n(n + 4.5) + n(n + 8) = (n + 8)(n + 4.5)

n^2 + 4.5n + n^2 + 8n = n^2 + 4.5n + 8n + 36

2n^2 + 12.5n = n^2 + 12.5n + 36

n^2 = 36

n = 6 or -6

Since n can’t be negative, n = 6.

Answer: C

Abhishek009 · Answer

RESPONDING TO A PM IN THIS REGARD -

Time required to complete the task will be  \sqrt{ab}

It can be applied to all such cases without any restriction !!

Jihyo · Answer

let us assume the time taken to do the work together = x hours

Time taken by A to do the work alone = x+8 hours
Time taken by B to do the work alone =x+4.5 hours

L.C.M=(x+8)(x+4.5)=TOTAL WORK
Rate of A = x+4.5 part of work per hour
Rate of B= x+8 part of work per hour
Rate of A & B working together= (x+4.5+x+8)=(2x+12.5) part of work per hour

RATE*TIME TAKEN=TOTAL WORK
=>(2x+12.5)*x=(x+8)(x+4.5)
=>x^2=36
=>x=6

Answer:6 hours.

Kinshook · Answer

Given:  
1. Two workers A and B are engaged to do a work. 
2. A working alone takes 8 hours more to complete the job than if both worked together.
3. If B worked alone, he would need 4.5 hours more to complete the job than they both working together.

Asked:  What time would they take to do the work together ?

Let us assume that they take x hours working together to complete the job.

A working alone takes 8 hours more to complete the job than if both worked together. 
A takes (x+8) hours to complete the job.

If B worked alone, he would need 4.5 hours more to complete the job than they both working together.  
B takes (x+4.5) hours to complete the job.

They take x hours to complete the job together. 
1/(x+8) + 1/(x+4.5) = 1/x
2x^2 + 12.5x = (x+8)(x+4.5) = x^2 + 12.5x + 36
x^2 = 36
x = 6 hours

They will take 6 hours to complete the work together.

IMO C

krishna_sunder_ · Answer

Bunuel   sujoykrdatta

RATE         *            TIME             =WORK

a+b                          x                 =1
a                              x+8             =1
b                              x+4.5          =1

therefore
(a+b)x = a(x+8) => Bx = 8A    --------------1
the same way
(a+b)x = b(x+4.5) => Ax = 4.5B  ---------------2

multiplying 1 and 2
we get

(B*x) * (A*x) = (8*A)*(4.5*B)
A*B cancel's out in both sides giving

x*x = 8*4.5
x = 6

HarshavardhanR · Answer

https://gmatclub.com/forum/download/file.php?id=83555 Harsha GMAT-Club-Forum-lkw3mpl4.png

placeat · Answer

root of a.b = root8*4.5 =root 36 =6

Two workers A and B are engaged to do a work. A working alone takes 8

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Two workers A and B are engaged to do a work. A working alone takes 8

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