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Two workers A and B are engaged to do a work. A working alone takes 8

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Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 24 Jan 2020, 02:05
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Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours


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Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 24 Jan 2020, 02:38
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Bunuel wrote:
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours


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\((A+B)t=1\) or \((A+B)=\frac{1}{t}\)
\(A(t+8)=1\) or \(A=\frac{1}{t+8}\)
\(B(t+4.5)=1\) or \(B=\frac{1}{t+4.5}\)

\(\frac{1}{t+8}+\frac{1}{t+4.5}=\frac{1}{t}\)

\(\frac{1}{t+4.5}=\frac{1}{t}-\frac{1}{t+8}\)

\(\frac{1}{t+4.5}=\frac{t+8-t}{t(t+8)}\)

\(t(t+8)=8(t+4.5)\)

\(t^2+8t=8t+36\)

\(t^2=36\)

\(t=6\)

Answer is (C)
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Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 24 Jan 2020, 04:35
Question:
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together?


Solution:
Let A and B together take t hours to complete the work.
Thus, time taken by A = (t + 8) hrs and time taken by B = (t + 4.5) hrs

Thus, we can say that:
Work done by (A and B) in t hours = Work done by A in (t + 8) hours = Total work
=> (Work done by A in t hrs) + (Work done by B in t hrs) = (Work done by A in t hrs) + (Work done by A in 8 hrs)

Cancelling the (Work done by A in t hrs) from both sides:
(Work done by B in t hrs) = (Work done by A in 8 hrs)
=> Work done by B in 1 hr = Work done by A in (8/t) hrs ... (i)


Similarly, we have:
Work done by (A and B) in t hours = Work done by B in (t + 4.5) hours = Total work
=> (Work done by A in t hrs) + (Work done by B in t hrs) = (Work done by B in t hrs) + (Work done by B in 4.5 hrs)

Cancelling the (Work done by B in t hrs) from both sides:
(Work done by A in t hrs) = (Work done by B in 4.5 hrs)
=> Work done by B in 1 hr = Work done by A in (t/4.5) hrs ... (ii)

Thus, from (i) and(ii):
8/t = t/4.5

=> \(t^2 = 36\)
=> t = 6 hrs

Answer C


Alternate approach
Let time taken by A and B together be t hours
Thus, time taken by A = (t + 8) hrs and time taken by B = (t + 4.5) hrs

thus, equating work done by A and B in 1 hour:
1/(t + 8) + 1/(t + 4.5) = 1/t

Solving, we get: t = 6 hours
Answer C
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Re: Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 24 Jan 2020, 08:58
1
Bunuel wrote:
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours


Are You Up For the Challenge: 700 Level Questions

A short little formula exists which can solve it in 10 secs -

\(\sqrt{8*4.5}\)

\(= \sqrt{36}\)

\(= 6\) , Answer must be (C)
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Re: Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 28 Jan 2020, 06:49
Bunuel wrote:
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours


r=w/t

(a+b)=1/t
a=1/t+8
b=1/t+4.5
(1/t+8)+(1/t+4.5)=1/t
2t^2+12.5t=t^2+12.5t+36
t^2=36 (t>0) t=6

Ans (C)
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Re: Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 11 Feb 2020, 17:48
Quote:

A short little formula exists which can solve it in 10 secs -

\(\sqrt{8*4.5}\)

\(= \sqrt{36}\)

\(= 6\) , Answer must be (C)


Abhishek009

Any theory or links on how this is achievable and in what conditions it usually works?

Thank you!
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Re: Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 16 Feb 2020, 07:03
1
Bunuel wrote:
Two workers A and B are engaged to do a work. A working alone takes 8 hours more to complete the job than if both worked together. If B worked alone, he would need 4.5 hours more to complete the job than they both working together. What time would they take to do the work together ?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours
E. 8 hours


Are You Up For the Challenge: 700 Level Questions


Let’s let n = the number of hours it takes to complete the job when A and B work together; thus, their combined rate is 1/n. Since A alone takes 8 hours more than if they work together, then A’s rate is 1/(n + 8). And since B alone takes 4.5 hours more than if they work together, then B’s rate is 1/(n + 4.5).

Thus, , we can create the rate equation:

1/(n + 8) + 1/(n + 4.5) = 1/n

Multiplying by n(n + 8)(n + 4.5), we have:

n(n + 4.5) + n(n + 8) = (n + 8)(n + 4.5)

n^2 + 4.5n + n^2 + 8n = n^2 + 4.5n + 8n + 36

2n^2 + 12.5n = n^2 + 12.5n + 36

n^2 = 36

n = 6 or -6

Since n can’t be negative, n = 6.

Answer: C
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Re: Two workers A and B are engaged to do a work. A working alone takes 8  [#permalink]

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New post 20 Feb 2020, 07:21
TheNightKing wrote:
Quote:

A short little formula exists which can solve it in 10 secs -

\(\sqrt{8*4.5}\)

\(= \sqrt{36}\)

\(= 6\) , Answer must be (C)


Abhishek009

Any theory or links on how this is achievable and in what conditions it usually works?

Thank you!


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Quote:
Two workers A and B are engaged to do a work. A working alone takes a hours more to complete the job than if both worked together. If B worked alone, he would need b hours more to complete the job than they both working together. What time would they take to do the work together ?


Time required to complete the task will be \(\sqrt{ab}\)

It can be applied to all such cases without any restriction !!
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Thanks and Regards

Abhishek....

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Re: Two workers A and B are engaged to do a work. A working alone takes 8   [#permalink] 20 Feb 2020, 07:21
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