Last visit was: 25 Apr 2026, 07:17 It is currently 25 Apr 2026, 07:17
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,827
Own Kudos:
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,827
Kudos: 811,194
 [23]
1
Kudos
Add Kudos
22
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
cutegirlsimran
Joined: 22 Feb 2015
Last visit: 16 Jul 2016
Posts: 51
Own Kudos:
168
 [9]
Given Kudos: 3
Location: United States
Concentration: Finance, Operations
GMAT Date: 04-01-2015
GPA: 3.98
7
Kudos
Add Kudos
2
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,827
Own Kudos:
811,194
 [7]
Given Kudos: 105,878
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,827
Kudos: 811,194
 [7]
Kudos
Add Kudos
7
Bookmarks
Bookmark this Post
General Discussion
User avatar
peachfuzz
Joined: 28 Feb 2014
Last visit: 27 Jan 2018
Posts: 268
Own Kudos:
369
 [5]
Given Kudos: 132
Location: United States
Concentration: Strategy, General Management
Products:
Posts: 268
Kudos: 369
 [5]
4
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Possibilities include
1novel, 3 poems
6! / 1!5! × 4! /3! 1! =24

2 novels, 3 poems
6!/2! 4! × 4!/2! 2! =90

0 novels, 4 poems
=1

24+90+1=115

B. 115
User avatar
lipsi18
Joined: 26 Dec 2012
Last visit: 30 Nov 2019
Posts: 131
Own Kudos:
57
 [1]
Given Kudos: 4
Location: United States
Concentration: Technology, Social Entrepreneurship
WE:Information Technology (Computer Software)
Posts: 131
Kudos: 57
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Novel=N,Poem book=P; therefore 10=4+Novels =>N=6;P=4

The final selection would be = 2N and 2P +1N and 3P + 4P =6C2*4C2 + 6C1*4C3 + 4C4 = 90+24+1=115

Hence answer is B

Thanks,
User avatar
Bowtye
Joined: 13 Nov 2014
Last visit: 29 Jun 2018
Posts: 90
Own Kudos:
127
 [1]
Given Kudos: 28
GMAT 1: 740 Q50 V40
Products:
GMAT 1: 740 Q50 V40
Posts: 90
Kudos: 127
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A reading list for a certain course consists of 10 books, of which 4 are poems and the rest are novels. Each student is required to read a selection of 4 books from the list, including at most 2 novels. How many selections of 4 books satisfy the requirements?

A. 90
B. 115
C. 130
D. 144
E. 195

Kudos for a correct solution.


Options with two novels: 6C2 * 4C2 = 90

Options with one novel: 4C3 * 6C1 = 24

Option with no novel: 4C4 = 1

so 90+24+1 = 115

Answer is B
User avatar
KS15
Joined: 21 May 2013
Last visit: 25 Jul 2019
Posts: 531
Own Kudos:
259
 [1]
Given Kudos: 608
Posts: 531
Kudos: 259
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A reading list for a certain course consists of 10 books, of which 4 are poems and the rest are novels. Each student is required to read a selection of 4 books from the list, including at most 2 novels. How many selections of 4 books satisfy the requirements?

A. 90
B. 115
C. 130
D. 144
E. 195

Kudos for a correct solution.

Required selection=(4C2*6C2)+(6C1*4C3)+(4C4)
=90+24+1
=115
Answer B
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,711
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A reading list for a certain course consists of 10 books, of which 4 are poems and the rest are novels. Each student is required to read a selection of 4 books from the list, including at most 2 novels. How many selections of 4 books satisfy the requirements?

A. 90
B. 115
C. 130
D. 144
E. 195

We are given that a course reading list contains 4 poems and 6 novels. We need to determine the number of ways a student can select 4 books if at most 2 novels can be selected.

Scenario one: 4 poems are selected.

4 poems can be selected in 4C4 = 1 way.

Scenario two: 1 novel and 3 poems are selected.

3 poems can be selected in 4C3 = 4!/[3!(4-3)!] = (4 x 3 x 2)/3! = 4 ways, and 1 novel can be selected in 6C1 = 6 ways.

Thus, 3 poems and 1 novel can be selected in 4 x 6 = 24 ways.

Scenario three: 2 novels and 2 poems are selected.

2 poems can be selected in 4C2 = 4!/[2!(4-2)!] = (4 x 3)/2! = 6 ways, and 2 novels can be selected in 6C2 = 6!/[2!(6-2)!] = (6 x 5)/2! = 15 ways.

Thus, 2 poems and 2 novels can be selected in 6 x 15 = 90 ways.

All 4 books with at most 2 novels can be selected in 1 + 24 + 90 = 115 ways.

Answer: B
User avatar
Hero8888
Joined: 29 Dec 2017
Last visit: 14 Apr 2019
Posts: 299
Own Kudos:
348
 [1]
Given Kudos: 273
Location: United States
Concentration: Marketing, Technology
GMAT 1: 630 Q44 V33
GMAT 2: 690 Q47 V37
GMAT 3: 710 Q50 V37
GPA: 3.25
WE:Marketing (Telecommunications)
GMAT 3: 710 Q50 V37
Posts: 299
Kudos: 348
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A reading list for a humanities course consists of 10 books, of which 4 are biographies and the rest are novels. Each student is required to read a selection of 4 books from the list, including 2 or more biographies. How many selections of 4 books satisfy the requirements?

A. 90
B. 115
C. 130
D. 144
E. 195

Total: 4B and 6N
Possible outcomes (2B,2N) + (3B,1N) + (4B)
4!/2!*2! * 6!/4!*2! + 4!/3!*1! * 6!/1!*5! + 4!/4! = 90 + 24 +1 = 115. Answer (B)
User avatar
JeffTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 04 Mar 2011
Last visit: 05 Jan 2024
Posts: 2,974
Own Kudos:
Given Kudos: 1,646
Status:Head GMAT Instructor
Affiliations: Target Test Prep
Expert
Expert reply
Posts: 2,974
Kudos: 8,711
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
A reading list for a humanities course consists of 10 books, of which 4 are biographies and the rest are novels. Each student is required to read a selection of 4 books from the list, including 2 or more biographies. How many selections of 4 books satisfy the requirements?

A. 90
B. 115
C. 130
D. 144
E. 195

We can break this problem into scenarios:

Scenario 1: 2 biographies and 2 novels

The number of ways to select 2 biographies is 4C2 = 4!/[2! x (4 - 2)! = 4!/(2! x 2!) = (4 x 3)/2! = 6.

The number of ways to select 2 novels is 6C2 = 6!/[2! x (6 - 2)!]= 6!/(2! x 4!) =(6 x 5)/2! = 15.

So there are a total of 6 x 15 = 90 ways for this scenario.

Scenario 2: 3 biographies and 1 novel

The number of ways to select 3 biographies is 4C3 = 4.

The number of ways to select 1 novels is 6C1 = 6.

So there are a total of 4 x 6 = 24 ways for this scenario.

Scenario 3: 4 biographies

The number of ways to select 4 biographies is 4C4 = 1.

So there is only 1 way for this scenario.

So there are a total of 90 + 24 + 1 = 115 ways to choose 4 books that consist 2 or more biographies.

Answer: B
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,984
Own Kudos:
Posts: 38,984
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109827 posts
Tuck School Moderator
852 posts