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15 Aug 2018, 05:14
Kudos
Bookmarks
C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
44% (00:35) correct
56%
(02:41)
wrong
based on 9
sessions
History
Date
Time
Result
Not Attempted Yet
The remainder when 15^23 + 23^23 is divided by 19 is
A) 4
B) 15
C) 0
D) 18
E) 5
A) 4
B) 15
C) 0
D) 18
E) 5
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15 Aug 2018, 06:17
Kudos
Bookmarks
Remainder Property \(a^n\) + \(b^n\) is divisible by a+b if n is odd.
Here n=23 (odd). Now, a+b = 15+23 =38. Which is completely divisible by 19. Hence remainder is zero.
C is the answer.
Here n=23 (odd). Now, a+b = 15+23 =38. Which is completely divisible by 19. Hence remainder is zero.
C is the answer.
15 Aug 2018, 07:46
Kudos
Bookmarks
Afc0892
With (C) for the same reasons, well-explained Kudos added....
