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Updated on: 21 Dec 2019, 00:12
Originally posted by MathRevolution on 20 Dec 2019, 00:18.
Last edited by chetan2u on 21 Dec 2019, 00:12, edited 1 time in total.
Last edited by chetan2u on 21 Dec 2019, 00:12, edited 1 time in total.
Corrected the Q
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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81% (01:44) correct
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[GMAT math practice question]
\(x\) satisfies \(|x - 2| ≤ 3.\) What is the solution range satisfying \(\frac{1}{3}(x + 4)\)?
A. \(-3 ≤ \frac{1}{3}(x + 4) ≤ 3 \)
B. \(-1 ≤ \frac{1}{3}(x + 4) ≤ 2 \)
C. \(-2 ≤ \frac{1}{3}x + 4) ≤ 1\)
D. \(1 ≤ \frac{1}{3}(x + 4) ≤ 3\)
E. \(0 ≤ \frac{1}{3}(x + 4) ≤ 3\)
\(x\) satisfies \(|x - 2| ≤ 3.\) What is the solution range satisfying \(\frac{1}{3}(x + 4)\)?
A. \(-3 ≤ \frac{1}{3}(x + 4) ≤ 3 \)
B. \(-1 ≤ \frac{1}{3}(x + 4) ≤ 2 \)
C. \(-2 ≤ \frac{1}{3}x + 4) ≤ 1\)
D. \(1 ≤ \frac{1}{3}(x + 4) ≤ 3\)
E. \(0 ≤ \frac{1}{3}(x + 4) ≤ 3\)
20 Dec 2019, 23:53
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MathRevolution
\(|x-2|≤ 3\) MEANS \(-3≤ x-2≤ 3.......-1≤ x≤ 5\)
Now we are looking for the range of \(\frac{1}{3}(x + 4)\)
So ADD 4 to above equation
\(-1+4≤ x+4≤ 5+4........3≤ x+4≤ 9\)
then divide all terms by 3..
\(\frac{1}{3}*3≤ \frac{1}{3}(x+4)≤ \frac{1}{3}*9\) ..........\(1 ≤ \frac{1}{3}(x + 4) ≤ 3\)
General Discussion
20 Dec 2019, 22:00
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Can anyone please explain this question ?
Posted from my mobile device
Posted from my mobile device
